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| 1 | +class Solution { |
| 2 | + |
| 3 | + int[][][] dp; |
| 4 | + public int findMaxForm(String[] strs, int m, int n) { |
| 5 | + dp= new int[m+1][n+1][strs.length]; |
| 6 | + return helper(strs,m,n,0); |
| 7 | + } |
| 8 | + |
| 9 | + int helper(String[] strs,int zero,int one,int index){ |
| 10 | + if(index==strs.length || zero + one == 0){ |
| 11 | + return 0; |
| 12 | + } |
| 13 | + |
| 14 | + if(dp[zero][one][index]>0){ |
| 15 | + return dp[zero][one][index]; |
| 16 | + } |
| 17 | + |
| 18 | + int[] count = count(strs[index]); |
| 19 | + |
| 20 | + //consider changes the zero ad one |
| 21 | + int consider=0; |
| 22 | + |
| 23 | + if(zero >=count[0] && one>=count[1]){ |
| 24 | + consider = 1 + helper(strs,zero-count[0],one-count[1],index+1); |
| 25 | + } |
| 26 | + |
| 27 | + int skip = helper(strs,zero,one,index+1); |
| 28 | + |
| 29 | + //skip |
| 30 | + dp[zero][one][index]=Math.max(consider,skip);; |
| 31 | + return dp[zero][one][index]; |
| 32 | + |
| 33 | + } |
| 34 | + |
| 35 | + int[] count(String s){ |
| 36 | + int[] count=new int[2]; |
| 37 | + for(char c: s.toCharArray()){ |
| 38 | + count[c-'0']++; |
| 39 | + } |
| 40 | + return count; |
| 41 | + } |
| 42 | +} |
| 43 | + |
| 44 | +class Solution { |
| 45 | + |
| 46 | + int[][] dp; |
| 47 | + public int findMaxForm(String[] strs, int m, int n) { |
| 48 | + dp= new int[m+1][n+1]; |
| 49 | + |
| 50 | + for(String s:strs){ |
| 51 | + int[] count = count(s); |
| 52 | + //zero m-count[0] ---- 0 |
| 53 | + //one n - count[1] ---- 0 |
| 54 | + for(int zero=m;zero>=count[0];zero--){ |
| 55 | + for(int one=n; one>=count[1]; one--){ |
| 56 | + dp[zero][one] = Math.max(dp[zero-count[0]][one-count[1]] +1 , dp[zero][one]); |
| 57 | + } |
| 58 | + } |
| 59 | + } |
| 60 | + |
| 61 | + |
| 62 | + return dp[m][n]; |
| 63 | + } |
| 64 | + |
| 65 | + int[] count(String s){ |
| 66 | + int[] count=new int[2]; |
| 67 | + for(char c: s.toCharArray()){ |
| 68 | + count[c-'0']++; |
| 69 | + } |
| 70 | + return count; |
| 71 | + } |
| 72 | +} |
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