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| 1 | +class Solution { |
| 2 | + public String removeDuplicates(String s, int k) { |
| 3 | + Stack<Character> main = new Stack<>(); |
| 4 | + |
| 5 | + for(char c: s.toCharArray()){ |
| 6 | + Stack<Character> temp = new Stack<>(); |
| 7 | + temp.push(c); |
| 8 | + |
| 9 | + while(!main.isEmpty() && main.peek()==c){ |
| 10 | + temp.push(main.pop()); |
| 11 | + } |
| 12 | + |
| 13 | + if(temp.size()!=k){ |
| 14 | + while(!temp.isEmpty()){ |
| 15 | + main.push(temp.pop()); |
| 16 | + } |
| 17 | + } |
| 18 | + } |
| 19 | + |
| 20 | + StringBuilder sb= new StringBuilder(); |
| 21 | + |
| 22 | + while(!main.isEmpty()){ |
| 23 | + sb.append(main.pop()); |
| 24 | + } |
| 25 | + |
| 26 | + return sb.reverse().toString(); |
| 27 | + } |
| 28 | +} |
| 29 | + |
| 30 | +class Solution { |
| 31 | + public String removeDuplicates(String s, int k) { |
| 32 | + Stack<int[]> main = new Stack<>(); |
| 33 | + |
| 34 | + for(char c: s.toCharArray()){ |
| 35 | + if(!main.isEmpty() && main.peek()[0] == c){ |
| 36 | + main.peek()[1]++; |
| 37 | + } |
| 38 | + else{ |
| 39 | + main.push(new int[]{c,1}); |
| 40 | + } |
| 41 | + |
| 42 | + if(main.peek()[1]==k){ |
| 43 | + main.pop(); |
| 44 | + } |
| 45 | + } |
| 46 | + |
| 47 | + StringBuilder sb= new StringBuilder(); |
| 48 | + |
| 49 | + while(!main.isEmpty()){ |
| 50 | + int[] top = main.pop(); |
| 51 | + |
| 52 | + while(top[1]-->0) |
| 53 | + sb.append((char) top[0]); |
| 54 | + } |
| 55 | + |
| 56 | + return sb.reverse().toString(); |
| 57 | + } |
| 58 | +} |
| 59 | + |
| 60 | +class Solution { |
| 61 | + public String removeDuplicates(String s, int k) { |
| 62 | + int count = 1; |
| 63 | + for(int i=1;i<s.length();i++){ |
| 64 | + if(s.charAt(i)==s.charAt(i-1)){ |
| 65 | + count++; |
| 66 | + } |
| 67 | + else{ |
| 68 | + count=1; |
| 69 | + } |
| 70 | + |
| 71 | + if(count==k){ |
| 72 | + String reduced = s.substring(0,i-k+1) + s.substring(i+1); |
| 73 | + return removeDuplicates(reduced,k); |
| 74 | + } |
| 75 | + } |
| 76 | + |
| 77 | + return s; |
| 78 | + } |
| 79 | +} |
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