地址: https://leetcode-cn.com/problems/excel-sheet-column-number/
给定一个Excel表格中的列名称,返回其相应的列序号。 例如,
A -> 1
B -> 2
C -> 3
...
Z -> 26
AA -> 27
AB -> 28
...
示例 1:
输入: "A"
输出: 1
示例 2:
输入: "AB"
输出: 28
示例 3:
输入: "ZY"
输出: 701
class Solution:
def titleToNumber(self, columnTitle: str) -> int:
dic = {j:i for i,j in enumerate('ABCDEFGHIJKLMNOPQRSTUVWXYZ',1)}
columnTitle = columnTitle[::-1]
ans = 0
for i in range(len(columnTitle)):
ans += dic[columnTitle[i]] * 26**i
return ans
class Solution:
def titleToNumber(self, columnTitle: str) -> int:
dict_letter = {'A':1, 'B':2, 'C':3, 'D':4, 'E':5, 'F':6, 'G':7,
'H':8, 'I':9, 'J':10, 'K':11, 'L':12, 'M':13, 'N':14,
'O':15, 'P':16, 'Q':17, 'R':18, 'S':19, 'T':20,
'U':21, 'V':22, 'W':23, 'X':24, 'Y':25, 'Z':26,}
len_letter = len(columnTitle)
num = 0
for i in range(len_letter-1):
l = dict_letter.get(columnTitle[i])
num = num + l * 26 ** (len_letter-1-i)
num = num + dict_letter.get(columnTitle[-1])
return num