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@@ -55,21 +59,22 @@ bypass diodes activate in the shaded submodules, and the other modules operate
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at higher voltage to match the voltage of unshaded parallel strings.
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I simulated perpendicular shade on the first half of the first module in the
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string, while the rest of the strings were unaffected. This could be like a
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chimney. Then I increased the number of unaffected strings to see if it changed
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string, while the rest of the strings were unshaded. For example, this shade could be caused by a
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chimney. Then I increased the number of unshaded strings to see if it changed
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the effect. The effect of a shadow perpendicular to the string caused bypass
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diodes to trigger, but even after 20 strings, the IV curve of the system
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appears unaffected and the total power loss is only 0.85% for the system
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compared to unshaded.
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diodes to trigger. Adding more strings did not stop the bypass diodes from triggering, even after 20 parallel
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strings. The IV curve of the system had a kink until 4 unshaded parallel strings were added, but after 9 unshaded parallel strings were added, the IV curve
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appeared unaffected. After 19 unshaded parallel strings were added, the total power loss was only 0.85% for the system
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compared to unshaded. However, the power loss in the shaded string was about 15%.
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Here is the IV curve of the 20 string PV system with perpendicular shade on
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1st module of 1st string from the Jupyter notebook. It looks unaffected!
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Here is the IV curve of the 20 string PV system with perpendicular shade on the
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1st module of the 1st string from the Jupyter notebook. It looks unaffected!
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Now check out the IV curve of the string with the shaded module. It should
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be generating about 3200[W], but even though it's lost about 500[W], it
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still operates at 5[A], nearly the same current as the others strings. It
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still operates at 5[A], nearly the same current as the other strings. It
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still has to operate at the same voltage as the other strings, 538.7[V] in
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this example, so how does it do it with 2 bypass diodes activated?
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@@ -100,12 +105,20 @@ a scattershot of scenarios and found that parallel string voltage began to domin
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Of course, that only applies in this contrived example, but it was interesting nonetheless.
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## Conclusion
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I wish I could say, "that's all there is to it." But as my first blog post
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says, electrical mismatch in crystalline silicon is very counter-intuitive.
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I wish I could say, that's all there is to it, but as I said in my first blog post,
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electrical mismatch in crystalline silicon is very counter-intuitive.
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That's why I created PVMismatch to begin with. I was tired of guessing and
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being wrong. So don't guess. Simulate with confidence, try PVMismatch, and
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let me know what you learn!
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## Epilogue
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So back to that rooftop with the diagonal shade line. It's a bit of both
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categories right? How do you think it will perform? Will it lose nearly
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all of its power or will bypass diodes active and save the day? Or maybe
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something in between or completely different. Try to analyze it using
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PVMismatch. If you need help I analyzed it in this Google Colab notebook:
1. Meyers, B., Mikofski, M. A., & Anderson, M. (2016). A Fast Parameterized Model for Predicting PV System Performance under Partial Shade Conditions. In IEEE (Ed.), 2016 IEEE 43rd Photovoltaic Specialists Conference (PVSC) (pp. 3173–3178). IEEE. [https://doi.org/10.1109/PVSC.2016.7750251](https://doi.org/10.1109/PVSC.2016.7750251)
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