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Create 1028. Recover a Tree From Preorder Traversal (#723)
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode() : val(0), left(nullptr), right(nullptr) {}
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* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
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* };
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*/
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class Solution {
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public:
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TreeNode* solve(string s, int& i, int depth) {
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int n = s.size();
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if (i >= n)
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return NULL;
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int j = i;
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while (j < n && s[j] == '-') {
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j++;
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}
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int dash = j - i;
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if (dash != depth)
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return NULL;
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i += dash;
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int num = 0;
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while (i < n && isdigit(s[i])) {
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num = num * 10 + (s[i] - '0');
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i++;
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}
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TreeNode* root = new TreeNode(num);
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root->left = solve(s, i, depth + 1);
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root->right = solve(s, i, depth + 1);
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return root;
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}
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TreeNode* recoverFromPreorder(string traversal) {
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int i = 0;
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return solve(traversal, i, 0);
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}
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};

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