代码优化，去除剑指offer10.1题斐波那契数列最后一种解法中fib[2]=2的一行代码

Author: Vongfong

docs/notes/剑指 Offer 题解 - 10~19.md

@@ -107,7 +107,6 @@ public class Solution {
 
     public Solution() {
         fib[1] = 1;
-        fib[2] = 2;
         for (int i = 2; i < fib.length; i++)
             fib[i] = fib[i - 1] + fib[i - 2];
     }