possible passwords times out of 6 letter password combination

Author: hammad-ibrahim

Diff for: .idea/workspace.xml

@@ -0,0 +1,29 @@
+# # Problem 1
+# """
+# Use Python to calculate how many different passwords can be formed with 6 lower case English letters
+#  (excludes any character not found in the English alphabet).
+# For a 1 letter password, there would be 26 possibilities.
+# For a 2 letter password, each letter is independent of the other, so there would be 26 times 26 possibilities.
+# Using this information, print the amount of possible passwords that can be formed with 6 letters.
+# """
+
+
+# Answer :-
+"""
+To calculate the number of possible 6-letters passwords we use the fact that each letter in the password
+ can be chosen independently form 26 lowercase English letters.
+
+FOR each position int the password :
+- There are 26 possible choices for the first letter.
+- There are 26 possible choices for the second letter.
+- This pattern will continue for all the 6 letters.
+
+The total number of different password is 26* 26* 26* 26* 26*26 = 26 **6
+Calculating this, we get 308,915,776 possible passwords
+
+"""
+# let's give it a try ..
+
+english_letters = 26
+Password_letters = 6
+print(f" The  value of {str(english_letters ** Password_letters)} is the possible passwords  ")

Diff for: Python With Google--Crash Course on Python/Module01 - Hello Python/M1- Graded assesment.py

@@ -46,3 +46,7 @@
 # print the calculation stored int the "weeks_in_year" variables
 print(weeks_in_decade)
 
+# Skill 3 -- Use variables with assignment and arithmetic operators
+# Assignment of values to the variables
+
+