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Solve KMP & KMR
1 parent 1b2a513 commit 1384cb9

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2 files changed

+130
-124
lines changed

2 files changed

+130
-124
lines changed

KMP.cpp

+16-31
Original file line numberDiff line numberDiff line change
@@ -1,35 +1,20 @@
1-
#include<bits/stdc++.h>
1+
#include <bits/stdc++.h>
2+
23
using namespace std;
3-
#define FOR(i,a,b) for(int i = (a); i <= (b); ++i)
4-
#define FORD(i,a,b) for(int i = (b); i >= (a); --i)
5-
#define TRAV(x,T) for(auto& x: (T))
6-
#define ALL(T) T.begin(), T.end()
7-
#define TAB(T,a,b) (T)+a, (T)+((b)+1)
8-
#define VAR(x) #x<<" = "<<x<<" "
9-
#define SZ(x) (int)(x).size()
10-
#define Nwd __gcd
11-
#define pb push_back
12-
#define st first
13-
#define nd second
14-
#define lc (v<<1)
15-
#define rc (v<<1|1)
16-
typedef long long ll;
17-
typedef long double ld;
18-
typedef pair<int, int> pii;
19-
typedef pair<int, ll> pil;
20-
typedef pair<ll, int> pli;
21-
typedef pair<ll, ll> pll;
22-
typedef vector<int> vi;
23-
#define deb if(0)
4+
5+
const int NT = 1e6 + 2;
246

257
int Pi[NT];
8+
269
void Kmp(string s) {
27-
int n = SZ(s);
28-
s = "#" + s;
29-
FOR(i, 2, n) {
30-
int pref = Pi[i - 1];
31-
while(pref > 0 and s[pref + 1] != s[i]) pref = Pi[pref];
32-
if(s[pref + 1] == s[i]) pref++;
33-
Pi[i] = pref;
34-
}
35-
}
10+
int n = s.size();
11+
s = "#" + s;
12+
for (int i = 2; i <= n; i++) {
13+
int pref = Pi[i - 1];
14+
while (pref > 0 and s[pref + 1] != s[i])
15+
pref = Pi[pref];
16+
if (s[pref + 1] == s[i])
17+
pref++;
18+
Pi[i] = pref;
19+
}
20+
}

KMR.cpp

+114-93
Original file line numberDiff line numberDiff line change
@@ -1,117 +1,138 @@
1-
#include<bits/stdc++.h>
1+
#include <bits/stdc++.h>
2+
23
using namespace std;
3-
#define FOR(i,a,b) for(int i = (a); i <= (b); ++i)
4-
#define FORD(i,a,b) for(int i = (a); i >= (b); --i)
5-
#define pb push_back
6-
#define pocz first
7-
#define kon second.first
8-
#define poz second.second
9-
typedef long long ll;
10-
typedef long double ld;
11-
typedef pair<int, int> pii;
4+
125
const int N = 1e6 + 2;
136
const int R = 23;
147

15-
pair<int,pii> A[N];
8+
pair<int, pair<int, int>> A[N];
169
int KMR[N][R];
10+
1711
void kmr(string s) {
18-
int n = s.size() - 1;
19-
int r = log2(n) + 1, pot = 1;
20-
FOR(i, 1, n) {
21-
KMR[i][0] = s[i] - 'a' + 1;
12+
int n = s.size() - 1;
13+
int r = log2(n) + 1, pot = 1;
14+
15+
for (int i = 1; i <= n; i++) {
16+
KMR[i][0] = s[i] - 'a' + 1;
17+
}
18+
19+
for (int k = 1; k <= r; k++) {
20+
for (int i = 1; i <= n; i++) {
21+
if (i + pot > n)
22+
A[i] = {KMR[i][k - 1], {-1, i}};
23+
else
24+
A[i] = {KMR[i][k - 1], {KMR[i + pot][k - 1], i}};
2225
}
23-
FOR(k, 1, r) {
24-
FOR(i, 1, n) {
25-
if(i + pot > n) A[i] = { KMR[i][k - 1], {-1, i} };
26-
else A[i] = { KMR[i][k - 1], {KMR[i + pot][k - 1], i} };
27-
}
28-
sort(A + 1, A + (n + 1));
29-
int kl = 0;
30-
pii p = {-1,-1}, a; // poprzedni element
31-
FOR(i, 1, n) {
32-
a = {A[i].pocz, A[i].kon};
33-
if(p != a) {
34-
p = a;
35-
++kl;
36-
}
37-
KMR[A[i].poz][k] = kl;
38-
}
39-
pot *= 2;
26+
sort(A + 1, A + (n + 1));
27+
int kl = 0;
28+
pair<int, int> p = {-1, -1}, a; // previous element
29+
for (int i = 1; i <= n; i++) {
30+
a = {A[i].first, A[i].second.first};
31+
if (p != a) {
32+
p = a;
33+
++kl;
34+
}
35+
KMR[A[i].second.second][k] = kl;
4036
}
41-
cout<<"KMR:\n"; FOR(k, 0, r) { FOR(i, 1, n) cout<<KMR[i][k]<<" "; cout<<"\n"; } // wypisz tablice
37+
pot *= 2;
38+
}
39+
cout << "KMR:\n";
40+
for (int k = 0; k <= r; k++) {
41+
for (int i = 1; i <= n; i++)
42+
cout << KMR[i][k] << " ";
43+
cout << "\n";
44+
}
4245
}
4346

44-
int SA[N], RANK[N]; // SA - przechowuje informacje o kolejnosci w SA, RANK - informuje ktory leksykograficznie jest ity sufiks
47+
int SA[N], RANK[N]; // SA - przechowuje informacje o kolejnosci w SA, RANK -
48+
// informuje ktory leksykograficznie jest ity sufiks
4549
void sa(string s) { // suffix array
46-
int n = s.size() - 1;
47-
int r = log2(n) + 1; // ostatnia warstwa KMR
48-
FOR(i, 1, n) {
49-
SA[KMR[i][r]] = i;
50-
RANK[i] = KMR[i][r]; // RANK pomaga przy nawigacji po SA, jest to odwrotnosc SA
51-
}
52-
cout<<"SA:\n";
53-
FOR(i, 1, n) {
54-
cout<<SA[i]<<": ";
55-
FOR(j, SA[i], n) cout<<s[j]; cout<<"\n";
56-
}
57-
cout<<"RANK:\n";
58-
FOR(i, 1, n) cout<<RANK[i]<<" "; cout<<"\n";
50+
int n = s.size() - 1;
51+
int r = log2(n) + 1; // ostatnia warstwa KMR
52+
for (int i = 1; i <= n; i++) {
53+
SA[KMR[i][r]] = i;
54+
RANK[i] =
55+
KMR[i][r]; // RANK pomaga przy nawigacji po SA, jest to odwrotnosc SA
56+
}
57+
cout << "SA:\n";
58+
for (int i = 1; i <= n; i++) {
59+
cout << SA[i] << ": ";
60+
for (int j = SA[i]; j <= n; j++)
61+
cout << s[j];
62+
cout << "\n";
63+
}
64+
cout << "RANK:\n";
65+
for (int i = 1; i <= n; i++)
66+
cout << RANK[i] << " ";
67+
cout << "\n";
5968
}
6069

6170
int LCP[N];
6271

63-
int czescwspolna(string s, int a, int b) {
64-
int n = s.size() - 1, i = 0;
65-
while(a + i <= n && b + i <= n) {
66-
if(s[a + i] != s[b + i]) break;
67-
++i;
68-
}
69-
return i;
72+
int commonPart(string s, int a, int b) {
73+
int n = s.size() - 1, i = 0;
74+
while (a + i <= n && b + i <= n) {
75+
if (s[a + i] != s[b + i])
76+
break;
77+
++i;
78+
}
79+
return i;
7080
}
7181

7282
void lcp(string s) { // longest common prefix
73-
int n = s.size() - 1;
74-
FOR(i, 1, n) {
75-
if(RANK[i] == 1) LCP[1] = -1; // jezeli jest pierwszy leksykograficznie to -1 bo nie ma dla niego pary
76-
else LCP[RANK[i]] = czescwspolna(s, i, SA[RANK[i] - 1]);
77-
}
78-
cout<<"LCP:\n"; FOR(i, 1, n) cout<<LCP[i]<<" "; cout<<"\n";
83+
int n = s.size() - 1;
84+
for (int i = 1; i <= n; i++) {
85+
if (RANK[i] == 1)
86+
LCP[1] = -1; // jezeli jest pierwszy leksykograficznie to -1 bo nie ma dla
87+
// niego pary
88+
else
89+
LCP[RANK[i]] = commonPart(s, i, SA[RANK[i] - 1]);
90+
}
91+
cout << "LCP:\n";
92+
for (int i = 1; i <= n; i++)
93+
cout << LCP[i] << " ";
94+
cout << "\n";
7995
}
8096

81-
int porownaj(int a, int b, int c, int d) { // 0 - s(a,b) < s(c,d), 1 - s(a,b) == s(c,d), 2 - s(a,b) > s(c,d)
82-
int n = b - a + 1, m = d - c + 1, pot = 1, pota = -1, potb = -1, qa, qb;
83-
bool oa = 0, ob = 0;
84-
FOR(i, 2, 20) {
85-
pot *= 2;
86-
if(pot > n && !oa) {
87-
pota = pot / 2;
88-
qa = i - 2; // nie jestem pewny dlaczego i - 2, a nie i - 1
89-
oa = 1;
90-
}
91-
if(pot > m && !ob) {
92-
potb = pot / 2;
93-
qb = i - 2; // ^^^ (same here lulz)
94-
ob = 1;
95-
}
96-
if(pot > n && pot > m ) break;
97+
int compare(
98+
int a, int b, int c,
99+
int d) { // 0 - s(a,b) < s(c,d), 1 - s(a,b) == s(c,d), 2 - s(a,b) > s(c,d)
100+
int n = b - a + 1, m = d - c + 1, pot = 1, pota = -1, potb = -1, qa, qb;
101+
bool oa = 0, ob = 0;
102+
for (int i = 2; i <= 20; i++) {
103+
pot *= 2;
104+
if (pot > n && !oa) {
105+
pota = pot / 2;
106+
qa = i - 2; // nie jestem pewny dlaczego i - 2, a nie i - 1
107+
oa = 1;
108+
}
109+
if (pot > m && !ob) {
110+
potb = pot / 2;
111+
qb = i - 2; // ^^^ (same here lulz)
112+
ob = 1;
97113
}
98-
pii x, y;
99-
x = {KMR[a][qa], KMR[b - pota + 1][qa]};
100-
y = {KMR[c][qb], KMR[d - potb + 1][qb]};
101-
if(x < y) return 0;
102-
else if(x == y) return 1;
103-
else return 2;
114+
if (pot > n && pot > m)
115+
break;
116+
}
117+
pair<int, int> x, y;
118+
x = {KMR[a][qa], KMR[b - pota + 1][qa]};
119+
y = {KMR[c][qb], KMR[d - potb + 1][qb]};
120+
if (x < y)
121+
return 0;
122+
else if (x == y)
123+
return 1;
124+
else
125+
return 2;
104126
}
105127

106128
signed main() {
107-
ios_base::sync_with_stdio(0);
108-
cin.tie(0);
109-
string s;
110-
cin>>s;
111-
//cin>>a>>b>>c>>d;
112-
s = "#" + s;
113-
kmr(s);
114-
sa(s);
115-
lcp(s);
116-
return 0;
117-
}
129+
ios_base::sync_with_stdio(0);
130+
cin.tie(0);
131+
string s;
132+
cin >> s;
133+
s = "#" + s;
134+
kmr(s);
135+
sa(s);
136+
lcp(s);
137+
return 0;
138+
}

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