ll-rshift.md

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Learn more about: __ll_rshift	__ll_rshift	09/02/2019	__ll_rshift_cpp __ll_rshift	__ll_rshift intrinsic ll_rshift intrinsic	ef13b732-d122-44a0-add9-f5544a2c4ab2

__ll_rshift

Microsoft Specific

Shifts a 64-bit value specified by the first parameter to the right, by a number of bits specified by the second parameter.

Syntax

__int64 __ll_rshift(
   __int64 Mask,
   int nBit
);

Parameters

Mask
[in] The 64-bit integer value to shift right.

nBit
[in] The number of bits to shift, modulo 64 on x64, and modulo 32 on x86.

Return value

The mask shifted by nBit bits.

Requirements

Intrinsic	Architecture
__ll_rshift	x86, x64

Header file <intrin.h>

Remarks

If the second parameter is greater than 64 on x64 (32 on x86), that number is taken modulo 64 (32 on x86) to determine the number of bits to shift. The ll prefix indicates that it's an operation on long long, another name for __int64, the 64-bit signed integral type.

Example

// ll_rshift.cpp
// compile with: /EHsc
// processor: x86, x64
#include <iostream>
#include <intrin.h>
using namespace std;

#pragma intrinsic(__ll_rshift)

int main()
{
   __int64 Mask = - 0x100;
   int nBit = 4;
   cout << hex << Mask << endl;
   cout << " - " << (- Mask) << endl;
   Mask = __ll_rshift(Mask, nBit);
   cout << hex << Mask << endl;
   cout << " - " << (- Mask) << endl;
}

Output

ffffffffffffff00
- 100
fffffffffffffff0
- 10

Note

If _ull_rshift has been used, the MSB of the right-shifted value would have been zero, so the desired result would not have been obtained in the case of a negative value.

END Microsoft Specific

See also

Compiler intrinsics
__ll_lshift
__ull_rshift