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test2merge.cpp
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//Time complexity: O(nlogn)
//ARRAY METHOD
#include <bits/stdc++.h>
using namespace std;
//function to merge the subarrays
void merge(int number[],int start,int end){
int mid = (start+end)/2;
int i = start; // start of the vector
int j = mid+1; // the start of the 2nd vector
int k = start; // start of the TEMPORARY array
//vector <int> temp;
int temp[100]; //temporary array
while(i<=mid && j<=end){
if(number[i] < number[j]){
//temp.push_back(number[i]);
temp[k] = number[i];
k++;
i++;
}
else{
//temp.push_back(number[j]);
temp[k] = number[j];
k++;
j++;
}
}
//This while loop is if the 1st array has remaining values
while(i<=mid){
//temp.push_back(number[i]);
temp[k] = number[i];
k++;
i++;
}
//This while loop is if the 2nd array has remaining values
while(j<=end){
//temp.push_back(number[j]);
temp[k] = number[j];
k++;
j++;
}
//We need to copy all element to original arrays
for(int i=start;i<=end;i++){
number[i] = temp[i];
}
//
// while(!temp.empty()){
//
//
// int value = temp.back();
// temp.pop_back();
// number.push_back(value);
//
//
//
// }
}
void mergeSort(int number[],int start,int end){
//if 1 or 0 elements in the vector, don't have to sort. just return
if(start>=end){
return; //return the vector
}
//Follow 3 steps
//1. Divide
int mid = (start+end)/2; //mid point
// 2. Recursively divide the vector
mergeSort(number,start,mid); // divide the vector into a single element from start to mid
mergeSort(number,mid+1,end); // divide the vector into a single element from mid+1 to end
// 3. Sort & merge the two parts
merge(number,start,end);
}
int main(){
int number[100];
//vector <int> number;
int n;
cin>>n; //no of elements
for(int i=0;i<n;i++){
// int value;
//
// cin >> value;
// number.push_back(value);
cin >> number[i];
}
//call merge function
//vector,start,end
mergeSort(number,0,n-1);
for(int i=0; i<n; i++){
cout << number[i] << " ";
}
// for(auto &v: number){
//
// cout << v << " ";
// }
//
return 0;
}