2149. Rearrange Array Elements by Sign

//the pattern of placing pos in even and neg values in odd
class Solution {
    public int[] rearrangeArray(int[] nums) {
        int n=1,p=0;
        int []ans=new int[nums.length];
        if(nums.length<2){
            return nums;
        }
        for(int i=0;i<nums.length;i++){
           if(nums[i]>0){
               ans[p]=nums[i];
               p+=2;
           }
           else{
               ans[n]=nums[i];
               n+=2;
           }
        }
        return ans;
    }
}