fix: Rewrite description to align with code and video (#220)

Author: hollowcrust

en/Search Algorithms/Floyd Cycle Detection Algorithm to Find Duplicate Number.md

@@ -1,38 +1,77 @@
-# Floyd Cycle Detection Algorithm to find duplicate number in an array
+# Floyd Cycle Detection Algorithm to find duplicate numbers in an array
 
 ## Problem Statement
 
 Given an array of integers containing `n + 1` integers, where each integer is in the range `[1, n]` inclusive. If there is only one duplicate number in the input array, this algorithm returns the duplicate number without modifying the original array, otherwise, it returns -1.
 
 ## Approach
+- We can imagine the array `arr` as a directed graph where each element is a node. `arr[i]` is the index of the node to which the i-th node points.
+- For example, given the `arr = [1, 3, 4, 2, 3]`, we can represent `arr` as the following <br></br>
+![image](images/graph_1.png)
 
-- Use the function `f(x) = arr[x]` to construct the sequence: 
-`arr[0]`, `arr[arr[0]]`, `arr[arr[arr[0]]]`, `arr[arr[arr[arr[0]]]]`, etc....
-- Each new element in the sequence is an element in `arr[]` at the index of the previous element.
-- Starting from `x = arr[0]`, it will produce a linked list with a cycle.
-- The cycle appears because `arr[]` contains duplicate elements(at least one). The duplicate value is an entrance to the cycle. 
+- Since there are duplicates in `arr`, a cycle exists in the directed graph as there is a path from node 3 to itself, `3 -> 2 -> 4 -> 3`.
+- The problem now becomes finding the entrance node to the cycle (3 in this case). 
+- We can use the Floyd Cycle Detection Algorithm (also known as the "Hare and Tortoise algorithm") to detect the entrance of the cycle.
+- The idea of the algorithm is to maintain two pointers, `hare` and `tortoise` that iterate the array at different "speeds" (just like the fable). The details are as follows:
 
+### The procedure
+- Using two pointers `hare` and `tortoise`.
+- Initiate `hare = tortoise = arr[0]`.
+- For every next step until `hare == tortoise` again, assign `hare = arr[arr[hare]]` and `tortoise = arr[tortoise]` (`hare` "jumps" 2 steps while `tortoise` "jumps" one step).
+- At this point, `hare == tortoise`, reset `tortoise = arr[0]` while keeping the value of `hare` in the above procedure.
+- For every next step until `hare == tortoise` again, assign `hare = arr[hare]` and `tortoise = arr[tortoise]` (this time `hare` only "jumps" one step).
+- When `tortoise == hare`, the entrance of the cycle is found, hence `hare` and `tortoise` represent the value of the duplicated element.
+- Return `tortoise` (also possible to return `hare`)
+  
 ## Time Complexity
 
-O(n)
+`O(n)`
 
 ## Space Complexity
 
-O(1) 
+`O(1)`, since we only use two extra variables as pointers.
 
-## Example
+## Example with step-by-step explanation
+![image](images/graph_2.png)
 
 ```
-arr = [3, 4, 8, 5, 9, 1, 2, 6, 7, 4]  
+arr = [3, 4, 8, 5, 9, 1, 2, 6, 7, 4]
 
-return value = 4
+hare = tortoise = arr[0] = 3
+
+1st step:
+  - hare = arr[arr[3]] = arr[5] = 1
+  - tortoise = arr[3] = 5
+2nd step:
+  - hare = arr[arr[1]] = arr[4] = 9
+  - tortoise = arr[5] = 1
+3rd step:
+  - hare = arr[arr[9]] = arr[4] = 9
+  - tortoise = arr[1] = 4
+4th step:
+  - hare = arr[arr[9]] = 9
+  - tortoise = arr[4] = 9
+
+tortoise = arr[0] = 3
+
+1st step:
+  - hare = arr[9] = 4
+  - tortoise = arr[3] = 5
+2nd step:
+  - hare = arr[4] = 9
+  - tortoise = arr[5] = 1
+3rd step:
+  - hare = arr[9] = 4
+  - tortoise = arr[1] = 4
+
+return tortoise = 4
 ```
 
 ## Code Implementation Links
 
 - [C++](https://github.com/TheAlgorithms/C-Plus-Plus/blob/master/search/floyd_cycle_detection_algo.cpp)
 - [C](https://github.com/TheAlgorithms/C/blob/master/searching/floyd_cycle_detection_algorithm.c)
-
 #### Video Explanation
 
-[YouTube video explaining the Floyd Cycle Detection algorithm](https://www.youtube.com/watch?v=B6smdk7pZ14)
+- [YouTube video explaining the Floyd Cycle Detection algorithm](https://www.youtube.com/watch?v=B6smdk7pZ14)
+- [Another Youtube video](https://www.youtube.com/watch?v=PvrxZaH_eZ4&t=1s)