Removing column formatting

Author: rchung95

01-slides/5_optimization.ipynb

@@ -198,9 +198,7 @@
         "The escape vent can carry only 4 kg of goods. The items are:\n",
         "\n",
         "-   Stereo: \\$3000, 4 kg\n",
-        "\n",
         "-   Laptop: \\$2000, 3 kg\n",
-        "\n",
         "-   Guitar: \\$1500, 1 kg\n",
         "\n",
         "We've established the brute force is not a valid general solution (although feasible in this case)\n",
@@ -209,72 +207,39 @@
         "\n",
         "## Guitar Row\n",
         "\n",
-        "::: columns\n",
-        "::: {.column width=\"50%\"}\n",
         "-   Each dynamic programming problem starts with a grid\n",
-        "\n",
         "-   Each cell contains a list of items that can fit at that point\n",
-        "\n",
         "-   For cell Guitar 1, a guitar will fit there. It will also fit in cell Guitar 2, 3, 4\n",
-        "\n",
         "-   Sounds redundant, but let's keep going\n",
-        ":::\n",
         "\n",
-        "::: {.column width=\"50%\"}\n",
         "![](images/dynamic.png)\n",
-        ":::\n",
-        ":::\n",
         "\n",
         "## Stereo Row\n",
         "\n",
-        "::: columns\n",
-        "::: {.column width=\"50%\"}\n",
         "-   In the second row, we can steal the stereo or the guitar.\n",
-        "\n",
         "-   At 1 kg, you can only steal the guitar, same as for every other cell until Stereo 4, at which point you can steal the stereo and only the stereo.\n",
-        ":::\n",
         "\n",
-        "::: {.column width=\"50%\"}\n",
         "![](images/dynamic.png)\n",
-        ":::\n",
-        ":::\n",
         "\n",
         "## Laptop Row\n",
         "\n",
-        "::: columns\n",
-        "::: {.column width=\"50%\"}\n",
         "-   Now we can steal all 3 items\n",
-        "\n",
         "-   In the first two columns, we still can only steal the guitar. But in Laptop 3, we can steal the laptop\n",
-        "\n",
         "-   Laptop 4 is the interesting step. We could steal only the stereo, or the laptop and something else for 1 kg. What is that 1 kg item?\n",
-        "\n",
         "-   According to the above row, the max value for 1 kg is the guitar!\n",
-        ":::\n",
         "\n",
-        "::: {.column width=\"50%\"}\n",
         "![](images/dynamic.png)\n",
-        ":::\n",
-        ":::\n",
         "\n",
         "## Solution\n",
         "\n",
-        "::: columns\n",
-        "::: {.column width=\"50%\"}\n",
         "-   If we stole the guitar and laptop, the total value is 3500, which is greater than just stealing the stereo\n",
-        "\n",
         "-   Thus, we should steal guitar and laptop\n",
-        ":::\n",
         "\n",
-        "::: {.column width=\"50%\"}\n",
         "![](images/dynamic.png)\n",
-        ":::\n",
-        ":::\n",
         "\n",
         "## Formula for each cell\n",
         "\n",
         "-   We skipped some very trivial steps in calculating cells aside from the last one\n",
-        "\n",
         "-   Here's the explicit formula to calculate each cell's value\n",
         "\n",
         "Let $i$ be the row and $j$ be the column.\n",