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First completed : June 07, 2024
Last updated : July 01, 2024
Related Topics : Tree, Depth-First Search, Binary Tree
Acceptance Rate : 67.95 %
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumNumbers(self, root: Optional[TreeNode]) -> int:
self.summ = 0
def helper(current: Optional[TreeNode], currSum: []) -> None :
if not current :
print(int(''.join(currSum)))
self.summ += int(''.join(currSum))
return
currSum.append(str(current.val))
if current.left and current.right :
helper(current.left, currSum)
helper(current.right, currSum)
elif current.left :
helper(current.left, currSum)
else :
helper(current.right, currSum)
currSum.pop()
helper(root, [])
return self.summ