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First completed : July 15, 2024
Last updated : July 15, 2024
Related Topics : Tree, Depth-First Search, Binary Tree
Acceptance Rate : 65.77 %
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def lowestCommonAncestor(self, root: 'TreeNode', p: 'TreeNode', q: 'TreeNode') -> 'TreeNode':
path = [root]
pPath = []
qPath = []
def dfs(path: List['TreeNode'], qPath: List['TreeNode'], pPath: List['TreeNode']) -> None :
if qPath and pPath :
return
if path[-1] == p :
pPath.extend(path)
if path[-1] == q :
qPath.extend(path)
if path[-1].left :
path.append(path[-1].left)
dfs(path, qPath, pPath)
path.pop()
if path[-1].right :
path.append(path[-1].right)
dfs(path, qPath, pPath)
path.pop()
dfs(path, qPath, pPath)
while len(qPath) < len(pPath) :
pPath.pop()
while len(qPath) > len(pPath) :
qPath.pop()
while qPath[-1] != pPath[-1] :
qPath.pop()
pPath.pop()
return pPath[-1]