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+ /*
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+ Write a function that takes in a Binary Tree and returns if that tree is symmetrical. A tree is symmetrical
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+ if the left and right subtrees are mirror images of each other.
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+
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+ Explanation:
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+
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+ 1. The code defines a class `BinaryTree` representing a binary tree node. It has an `int` value and pointers
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+ to its left and right children.
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+ 2. The `SymmetricalTree` function is the main entry point. It calls the helper function `treesAreMirrored`
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+ to check if the left and right subtrees are mirrored.
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+ 3. The `treesAreMirrored` function checks if two binary trees are mirrored. It uses recursion to compare
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+ corresponding nodes in the left and right subtrees.
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+ 4. In the `treesAreMirrored` function, the base case checks if both the left and right trees are non-null
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+ and have the same value. If so, it recursively checks if their subtrees are mirrored.
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+ 5. If either the left or right tree is null or their values are not equal, they are not mirrored.
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+ If both the left and right trees are null, they are considered mirrored.
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+ 6. In the `main` function, a binary tree is created for testing purposes.
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+ 7. The `SymmetricalTree` function is called to check if the binary tree is symmetrical.
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+ 8. The result is printed to the console.
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+ 9. Memory cleanup is performed by deleting the dynamically allocated nodes.
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+
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+ Note: This code snippet assumes the use of a C++ compiler and standard library.
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+ */
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#include < iostream>
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using namespace std ;
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