s3upload.py

#!/usr/bin/python
# -*- coding: utf-8 -*-
# s3upload.py
# It is an example that handles S3 buckets on AWS.
# It uses Resource API (high-level) of Boto3.
# Upload a local file to a S3 bucket.
# You must provide 1 parameter:
# BUCKET_NAME     = Name of the bucket
# OBJECT_NAME     = Object file name in the bucket
# LOCAL_FILE_NAME = Local file name

import sys
import os
import boto3
import botocore

def main():

    # Make a list of command line arguments, omitting the [0] element
    # which is the script itself.
    args = sys.argv[1:]
    if len(args) < 3:
        print('Not enough parameters.\n'\
              'Proper Usage is: python s3upload.py '\
              '<BUCKET_NAME> <OBJECT_NAME> <LOCAL_FILE_NAME>')
        sys.exit(1)

    bucket_name = args[0]
    key_name = args[1]
    local_file_name = args[2]
    print('Bucket:     ' + bucket_name)
    print('Object/Key: ' + key_name)
    print('Local file: ' + local_file_name)

    # Instantiate the service resource object
    s3_resource = boto3.resource('s3')

    if not os.path.isfile(local_file_name):
        print("Error: File Not Found!!")
        sys.exit(1)

    try:
        #  Instantiate the bucket object
        bucket = s3_resource.Bucket(bucket_name)
        print('Uploading object ...')
        # Upload object
        bucket.upload_file(local_file_name, key_name)
        print('Uploaded')

    except botocore.exceptions.ClientError as e:
        if e.response['Error']['Code'] == "NoSuchBucket":
            print("Error: Bucket does not exist!!")
        elif e.response['Error']['Code'] == "InvalidBucketName":
            print("Error: Invalid Bucket name!!")
        elif e.response['Error']['Code'] == "AllAccessDisabled":
            print("Error: You do not have access to the Bucket!!")
        else:
            raise

    return


# This is the standard boilerplate that calls the main() function.
if __name__ == '__main__':
    main()