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3 files changed +33
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| 170 | [ Two Sum III - Data Structure Design] ( https://leetcode.com/problems/two-sum-iii-data-structure-design ) | Easy | |
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| 171 | [ Excel Sheet Column Number] ( https://leetcode.com/problems/excel-sheet-column-number ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/ExcelSheetColumnNumber.java ) [ ![ Python] ( https://img.icons8.com/color/35/000000/python.png )] ( python/excel_sheet_column_number.py ) |
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| 172 | [ Factoring Trailing Zeroes] ( https://leetcode.com/problems/factorial-trailing-zeroes ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/FactorialTrailingZeros.java ) [ ![ Python] ( https://img.icons8.com/color/35/000000/python.png )] ( python/factorial_trailing_zeroes.py ) |
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- | 189 | [ Rotate Array] ( https://leetcode.com/problems/rotate-array ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/RotateArray.java ) |
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+ | 189 | [ Rotate Array] ( https://leetcode.com/problems/rotate-array ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/RotateArray.java ) [ ![ Python ] ( https://img.icons8.com/color/35/000000/python.png )] ( python/rotate_array.py ) |
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| 190 | [ Reverse Bits] ( https://leetcode.com/problems/reverse-bits ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/ReverseBits.java ) |
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| 191 | [ Number of One Bits] ( https://leetcode.com/problems/number-of-1-bits ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/NumberOf1Bit.java ) [ ![ Python] ( https://img.icons8.com/color/35/000000/python.png )] ( python/number_of_1_bits.py ) |
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| 198 | [ House Robber] ( https://leetcode.com/problems/house-robber ) | Easy | [ ![ Java] ( https://img.icons8.com/color/40/000000/java-coffee-cup-logo.png )] ( src/HouseRobber.java ) |
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class Solution :
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def trailingZeroes (self , n : int ) -> int :
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divisor , count = 5 , 0
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- while n // divisor > 0 :
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+ while divisor <= n :
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count += n // divisor
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divisor *= 5
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return count
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+ from typing import List
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+
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+
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+ class Solution :
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+ def rotate (self , nums : List [int ], k : int ) -> None :
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+ """
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+ Do not return anything, modify nums in-place instead.
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+ """
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+ k %= len (nums )
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+ if k == 0 :
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+ return
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+ temp = nums [- k :]
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+ for i in range (len (nums ) - 1 , k - 1 , - 1 ):
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+ nums [i ] = nums [i - k ]
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+ for i , val in enumerate (temp ):
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+ nums [i ] = val
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+
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+ def reverse (self , A , i , j ):
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+ while i < j :
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+ A [i ], A [j ] = A [j ], A [i ]
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+ i += 1
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+ j -= 1
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+
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+ # this is method no. 2 to solve it with O(1) space complexity
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+ def rotate_2 (self , A , k ):
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+ L = len (A )
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+ k %= L
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+ if k :
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+ self .reverse (A , 0 , L - 1 )
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+ self .reverse (A , 0 , k - 1 )
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+ self .reverse (A , k , L - 1 )
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