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1 | 1 | // https://leetcode.com/problems/longest-palindromic-substring |
| 2 | +// T: O(n^2) |
| 3 | +// S: O(1) |
2 | 4 |
|
3 | 5 | public class LongestPalindromicSubstring { |
4 | | - public static void main(String[] args) { |
5 | | - System.out.println(isPalindrome("caba", 1, 4)); |
6 | | - } |
7 | | - |
8 | | - public static String longestPalindrome(String s) { |
9 | | - final String s2 = new StringBuilder(s).reverse().toString(); |
10 | | - final int rows = s.length() + 1, columns = s2.length() + 1; |
11 | | - final int[][] dp = new int[2][columns]; |
12 | | - int maxLength = 0, startIndex = -1; |
13 | | - |
14 | | - for (int row = 1, i = 1 ; row < rows ; row++, i ^= 1) { |
15 | | - for (int column = 1 ; column < columns ; column++) { |
16 | | - dp[i][column] = s.charAt(row - 1) == s2.charAt(column - 1) ? dp[i ^ 1][column - 1] + 1 : 0; |
17 | | - if (dp[i][column] > maxLength && isPalindrome(s, row - dp[i][column], row)) { |
18 | | - maxLength = dp[i][column]; |
19 | | - startIndex = row - maxLength; |
20 | | - } |
| 6 | + public String longestPalindrome(String s) { |
| 7 | + if (s.length() < 2) return s; |
| 8 | + int maxLen = 0, startIndex = -1; |
| 9 | + for (int i = 0, len ; i < s.length() - 1 ; i++) { |
| 10 | + len = palindromeLengthFromCenter(s, i, i); |
| 11 | + if (s.charAt(i) == s.charAt(i + 1)) { |
| 12 | + len = Math.max(len, palindromeLengthFromCenter(s, i, i + 1)); |
| 13 | + } |
| 14 | + if (len > maxLen) { |
| 15 | + maxLen = len; |
| 16 | + startIndex = i - (maxLen - 1) / 2; |
21 | 17 | } |
22 | 18 | } |
23 | | - |
24 | | - return s.substring(startIndex, startIndex + maxLength); |
| 19 | + return s.substring(startIndex, startIndex + maxLen); |
25 | 20 | } |
26 | 21 |
|
27 | | - private static boolean isPalindrome(String s, int start, int end) { |
28 | | - for (int i = start ; i < start + (end - start) / 2 ; i++) { |
29 | | - if (s.charAt(i) != s.charAt(end - i - 1 + start)) { |
30 | | - return false; |
31 | | - } |
| 22 | + private int palindromeLengthFromCenter(String s, int left, int right) { |
| 23 | + while (left - 1 >= 0 && right + 1 < s.length() && s.charAt(left - 1) == s.charAt(right + 1)) { |
| 24 | + left--; |
| 25 | + right++; |
32 | 26 | } |
33 | | - return true; |
| 27 | + return right - left + 1; |
34 | 28 | } |
35 | 29 | } |
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