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| 1 | +#include <iostream> |
| 2 | +using namespace std; |
| 3 | +#include<stdio.h> |
| 4 | + |
| 5 | +int N[200],count,ans; |
| 6 | +void printCombination1(int [], int, int,int); |
| 7 | +void printCombination2(int [], int, int,int); |
| 8 | +void combinationUtil1(int [], int [], int, int, int, int,int); |
| 9 | +void combinationUtil2(int [], int [], int, int, int, int,int); |
| 10 | +int main() |
| 11 | +{ |
| 12 | + int a[100],T,k; |
| 13 | + cin>>T; |
| 14 | + for(int i=0;i<T;i++) |
| 15 | + { |
| 16 | + cin>>N[i]; |
| 17 | + } |
| 18 | + for(int g=0;g<T;g++){ |
| 19 | + ans=0;k=0; |
| 20 | + for(int i=2;i<=N[g];i++) |
| 21 | + { |
| 22 | + count=0; |
| 23 | + for(int j=1;j<=N[g];j++) |
| 24 | + { |
| 25 | + if(i%j==0) |
| 26 | + count++; |
| 27 | + if(count==3) |
| 28 | + break; |
| 29 | + } |
| 30 | + if(count==2) |
| 31 | + { |
| 32 | + a[k]=i; |
| 33 | + k++; |
| 34 | + } |
| 35 | + } |
| 36 | + printCombination1(a,k,4,g); |
| 37 | + printCombination2(a,k,2,g); |
| 38 | + if(ans==1) |
| 39 | + cout<<"YES"<<"\n"; |
| 40 | + else |
| 41 | + cout<<"NO"<<"\n"; |
| 42 | + } |
| 43 | + return 0; |
| 44 | +} |
| 45 | + |
| 46 | +void printCombination1(int arr[], int n, int r,int g) |
| 47 | +{ |
| 48 | + // A temporary array to store all combination one by one |
| 49 | + int data[r]; |
| 50 | + |
| 51 | + // all combination using temprary array 'data[]' |
| 52 | + combinationUtil1(arr, data, 0, n-1, 0, r,g); |
| 53 | +} |
| 54 | + |
| 55 | +void printCombination2(int arr[], int n, int r,int g) |
| 56 | +{ |
| 57 | + // A temporary array to store all combination one by one |
| 58 | + int data[r]; |
| 59 | + |
| 60 | + // all combination using temprary array 'data[]' |
| 61 | + combinationUtil2(arr, data, 0, n-1, 0, r,g); |
| 62 | +} |
| 63 | + |
| 64 | +void combinationUtil1(int arr[], int data[], int start, int end, |
| 65 | + int index, int r,int g) |
| 66 | +{ |
| 67 | + if (index == r) |
| 68 | + { |
| 69 | + if(N[g] == (data[0]*data[1]) + (data[1]*data[0]) ) |
| 70 | + ans=1; |
| 71 | + if(N[g] == (data[0]*data[1]) + (data[1]*data[2]) ) |
| 72 | + ans=1; |
| 73 | + if(N[g] == (data[0]*data[1]) + (data[1]*data[3]) ) |
| 74 | + ans=1; |
| 75 | + if(N[g] == (data[0]*data[2]) + (data[1]*data[0]) ) |
| 76 | + ans=1; |
| 77 | + if(N[g] == (data[0]*data[2]) + (data[1]*data[2]) ) |
| 78 | + ans=1; |
| 79 | + if(N[g] == (data[0]*data[2]) + (data[1]*data[3]) ) |
| 80 | + ans=1; |
| 81 | + if(N[g] == (data[0]*data[3]) + (data[2]*data[1]) ) |
| 82 | + ans=1; |
| 83 | + if(N[g] == (data[0]*data[3]) + (data[1]*data[0]) ) |
| 84 | + ans=1; |
| 85 | + if(N[g] == (data[0]*data[3]) + (data[1]*data[2]) ) |
| 86 | + ans=1; |
| 87 | + if(N[g] == (data[0]*data[3]) + (data[1]*data[3]) ) |
| 88 | + ans=1; |
| 89 | + if(N[g] == (data[2]*data[3]) + (data[0]*data[1]) ) |
| 90 | + ans=1; |
| 91 | + if(N[g] == (data[2]*data[3]) + (data[0]*data[2]) ) |
| 92 | + ans=1; |
| 93 | + if(N[g] == (data[2]*data[3]) + (data[0]*data[3]) ) |
| 94 | + ans=1; |
| 95 | + if(N[g] == (data[2]*data[3]) + (data[1]*data[2]) ) |
| 96 | + ans=1; |
| 97 | + if(N[g] == (data[2]*data[3]) + (data[1]*data[3]) ) |
| 98 | + ans=1; |
| 99 | + return; |
| 100 | + } |
| 101 | + if(ans==1) |
| 102 | + return; |
| 103 | + |
| 104 | + for (int i=start; i<=end && end-i+1 >= r-index; i++) |
| 105 | + { |
| 106 | + data[index] = arr[i]; |
| 107 | + combinationUtil1(arr, data, i+1, end, index+1, r,g); |
| 108 | + } |
| 109 | +} |
| 110 | + |
| 111 | +void combinationUtil2(int arr[], int data[], int start, int end, |
| 112 | + int index, int r,int g) |
| 113 | +{ |
| 114 | + if (index == r) |
| 115 | + { |
| 116 | + if(N[g] == (data[0]*data[1]) + (data[0]*data[1])) |
| 117 | + ans=1; |
| 118 | + return; |
| 119 | + } |
| 120 | + |
| 121 | + for (int i=start; i<=end && end-i+1 >= r-index; i++) |
| 122 | + { |
| 123 | + data[index] = arr[i]; |
| 124 | + combinationUtil2(arr, data, i+1, end, index+1, r,g); |
| 125 | + } |
| 126 | +} |
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