Table: Employees
+---------------+---------+ | Column Name | Type | +---------------+---------+ | employee_id | int | | employee_name | varchar | | manager_id | int | +---------------+---------+ employee_id is the primary key for this table. Each row of this table indicates that the employee with ID employee_id and name employee_name reports his work to his/her direct manager with manager_id The head of the company is the employee with employee_id = 1.
Write an SQL query to find employee_id of all employees that directly or indirectly report their work to the head of the company.
The indirect relation between managers will not exceed 3 managers as the company is small.
Return result table in any order without duplicates.
The query result format is in the following example:
Employees table: +-------------+---------------+------------+ | employee_id | employee_name | manager_id | +-------------+---------------+------------+ | 1 | Boss | 1 | | 3 | Alice | 3 | | 2 | Bob | 1 | | 4 | Daniel | 2 | | 7 | Luis | 4 | | 8 | Jhon | 3 | | 9 | Angela | 8 | | 77 | Robert | 1 | +-------------+---------------+------------+ Result table: +-------------+ | employee_id | +-------------+ | 2 | | 77 | | 4 | | 7 | +-------------+ The head of the company is the employee with employee_id 1. The employees with employee_id 2 and 77 report their work directly to the head of the company. The employee with employee_id 4 report his work indirectly to the head of the company 4 --> 2 --> 1. The employee with employee_id 7 report his work indirectly to the head of the company 7 --> 4 --> 2 --> 1. The employees with employee_id 3, 8 and 9 don't report their work to head of company directly or indirectly.
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