circle-and-rectangle-overlapping

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1401. Circle and Rectangle Overlapping (Medium)

You are given a circle represented as (radius, xCenter, yCenter) and an axis-aligned rectangle represented as (x1, y1, x2, y2), where (x1, y1) are the coordinates of the bottom-left corner, and (x2, y2) are the coordinates of the top-right corner of the rectangle.

Return true if the circle and rectangle are overlapped otherwise return false. In other words, check if there is any point (xi, yi) that belongs to the circle and the rectangle at the same time.

 

Example 1:

Input: radius = 1, xCenter = 0, yCenter = 0, x1 = 1, y1 = -1, x2 = 3, y2 = 1
Output: true
Explanation: Circle and rectangle share the point (1,0).

Example 2:

Input: radius = 1, xCenter = 1, yCenter = 1, x1 = 1, y1 = -3, x2 = 2, y2 = -1
Output: false

Example 3:

Input: radius = 1, xCenter = 0, yCenter = 0, x1 = -1, y1 = 0, x2 = 0, y2 = 1
Output: true

 

Constraints:

• 1 <= radius <= 2000
• -104 <= xCenter, yCenter <= 104
• -104 <= x1 < x2 <= 104
• -104 <= y1 < y2 <= 104

Related Topics

[Math] [Geometry]

Hints

Hint 1

Locate the closest point of the square to the circle, you can then find the distance from this point to the center of the circle and check if this is less than or equal to the radius.