Skip to content

Files

Latest commit

author
Shuo
Sep 16, 2021
a7e7771 · Sep 16, 2021

History

History
69 lines (56 loc) · 3.34 KB

File metadata and controls

69 lines (56 loc) · 3.34 KB

< Previous                  Next >

Design a data structure that supports adding new words and finding if a string matches any previously added string.

Implement the WordDictionary class:

  • WordDictionary() Initializes the object.
  • void addWord(word) Adds word to the data structure, it can be matched later.
  • bool search(word) Returns true if there is any string in the data structure that matches word or false otherwise. word may contain dots '.' where dots can be matched with any letter.

 

Example:

Input
["WordDictionary","addWord","addWord","addWord","search","search","search","search"]
[[],["bad"],["dad"],["mad"],["pad"],["bad"],[".ad"],["b.."]]
Output
[null,null,null,null,false,true,true,true]

Explanation
WordDictionary wordDictionary = new WordDictionary();
wordDictionary.addWord("bad");
wordDictionary.addWord("dad");
wordDictionary.addWord("mad");
wordDictionary.search("pad"); // return False
wordDictionary.search("bad"); // return True
wordDictionary.search(".ad"); // return True
wordDictionary.search("b.."); // return True

 

Constraints:

  • 1 <= word.length <= 500
  • word in addWord consists lower-case English letters.
  • word in search consist of  '.' or lower-case English letters.
  • At most 50000 calls will be made to addWord and search.

Related Topics

[String] [Depth-First Search] [Design] [Trie]

Similar Questions

  1. Implement Trie (Prefix Tree) (Medium)
  2. Prefix and Suffix Search (Hard)

Hints

Hint 1 You should be familiar with how a Trie works. If not, please work on this problem: Implement Trie (Prefix Tree) first.