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You are given an integer array coins of length n which represents the n coins that you own. The value of the ith coin is coins[i]. You can make some value x if you can choose some of your n coins such that their values sum up to x.

Return the maximum number of consecutive integer values that you can make with your coins starting from and including 0.

Note that you may have multiple coins of the same value.

 

Example 1:

Input: coins = [1,3]
Output: 2
Explanation: You can make the following values:
- 0: take []
- 1: take [1]
You can make 2 consecutive integer values starting from 0.

Example 2:

Input: coins = [1,1,1,4]
Output: 8
Explanation: You can make the following values:
- 0: take []
- 1: take [1]
- 2: take [1,1]
- 3: take [1,1,1]
- 4: take [4]
- 5: take [4,1]
- 6: take [4,1,1]
- 7: take [4,1,1,1]
You can make 8 consecutive integer values starting from 0.

Example 3:

Input: nums = [1,4,10,3,1]
Output: 20

 

Constraints:

  • coins.length == n
  • 1 <= n <= 4 * 104
  • 1 <= coins[i] <= 4 * 104

Related Topics

[Array] [Greedy]

Similar Questions

  1. Patching Array (Hard)

Hints

Hint 1 If you can make the first x values and you have a value v, then you can make all the values ≤ v + x
Hint 2 Sort the array of coins. You can always make the value 0 so you can start with x = 0.
Hint 3 Process the values starting from the smallest and stop when there is a value that cannot be achieved with the current x.