Given a string s
, sort it in decreasing order based on the frequency of characters, and return the sorted string.
Example 1:
Input: s = "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer.
Example 2:
Input: s = "cccaaa" Output: "aaaccc" Explanation: Both 'c' and 'a' appear three times, so "aaaccc" is also a valid answer. Note that "cacaca" is incorrect, as the same characters must be together.
Example 3:
Input: s = "Aabb" Output: "bbAa" Explanation: "bbaA" is also a valid answer, but "Aabb" is incorrect. Note that 'A' and 'a' are treated as two different characters.
Constraints:
1 <= s.length <= 5 * 105
s
consists of English letters and digits.
[Hash Table] [String] [Bucket Sort] [Counting] [Sorting] [Heap (Priority Queue)]
- Top K Frequent Elements (Medium)
- First Unique Character in a String (Easy)