Wrong typedef output

[moshe5745]

schema := jtdinfer.NewInferrer(jtdinfer.WithoutHints())
.Infer(`{"name":"Joe", "age": 52, "something_optional": true, "something_nullable": 1.1}`).IntoSchema()

j, _ := json.MarshalIndent(schema, "", "  ")
fmt.Println(string(j))

Output:

{
  "type": "string"
}

Am I doing something wrong?

[bombsimon]

Hello!

Great question and this might not be obvious, but since you're actually passing a string (of JSON), the idea is to use the InferStrings method.

schema := jtdinfer.
	InferStrings(
		[]string{`{"name":"Joe", "age": 52, "something_optional": true, "something_nullable": 1.1}`},
		jtdinfer.WithoutHints(),
	).
	IntoSchema()
                                                                                                      
j, _ := json.MarshalIndent(schema, "", "  ")
fmt.Println(string(j))

Output:

{
  "properties": {
    "age": {
      "type": "uint8"
    },
    "name": {
      "type": "string"
    },
    "something_nullable": {
      "type": "float64"
    },
    "something_optional": {
      "type": "boolean"
    }
  }
}

The Infer method is used to infer primitive Go types. The first example is inferring an actual string (not a string of JSON). The equivalent for your input would be something like this which also gives the same result:

schema := jtdinfer.
	NewInferrer(jtdinfer.WithoutHints()).
	Infer(map[string]any{
		"name":               "Joe",
		"age":                52,
		"something_optional": true,
		"something_nullable": 1.1,
	}).
	IntoSchema()
                                            
j, _ := json.MarshalIndent(schema, "", "  ")
fmt.Println(string(j))

What's happening under the hood when you call InferStrings is that it first runs json.Unmarsal to a map[string]any and calls Infer with the same inferrer for each line.

[bombsimon]

I created #7 which updates the readme and adds more examples, hope that helps!

[moshe5745]

Totally
Thanks for the help and this package