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Added solution for 2481
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impl Solution {
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// If n is 1, return 0. If n is divisible by 2, return the quotient after dividing it by 2. Else return n
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pub fn number_of_cuts(n: i32) -> i32 {
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if n == 1 {
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return 0;
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}
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if n % 2 == 0 {
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return n / 2;
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}
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return n;
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}
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}

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