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TIP102 Unit 1 Session 1 Standard (Click for link to problem statements)
- 💡 Difficulty: Easy
- ⏰ Time to complete: 5 mins
- 🛠️ Topics: List Iteration, Conditionals
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Established a set (2-3) of test cases to verify their own solution later.
- Established a set (1-2) of edge cases to verify their solution handles complexities.
- Have fully understood the problem and have no clarifying questions.
- Have you verified any Time/Space Constraints for this problem?
- The function
count_less_than()
should take a list of integersrace_time
s and an integerthreshold
and return the count of elements inrace_times
that are strictly less thanthreshold
.
HAPPY CASE
Input: race_times = [1, 2, 3, 4, 5, 6], threshold = 4
Expected Output: 3
Input: race_times = [5, 6, 7, 8], threshold = 7
Expected Output: 2
EDGE CASE
Input: race_times = [], threshold = 4
Expected Output: 0
Match what this problem looks like to known categories of problems, e.g. Linked List or Dynamic Programming, and strategies or patterns in those categories.
This problem falls under: List Iteration and Counting.
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Define a function that iterates through the list, counts how many elements are less than the threshold, and returns the count.
1. Define the function `count_less_than(race_times, threshold)`.
2. Initialize a variable `count` to 0.
3. Iterate through each element in `race_times`.
4. If an element is less than `threshold`, increment `count`.
5. Return `count`
- Forgetting to initialize the count variable.
- Incorrectly comparing elements to the threshold.
Implement the code to solve the algorithm.
def count_less_than(race_times, threshold):
# Initialize the count variable to 0
count = 0
# Iterate through each time in the race_times list
for time in race_times:
# If the time is less than the threshold, increment the count
if time < threshold:
count += 1
# Return the count of race times less than the threshold
return count
Review the code by running specific example(s) and recording values (watchlist) of your code's variables along the way.
Call the function with the provided examples:
print(count_less_than([1, 2, 3, 4, 5, 6], 4)) # Expected Output: 3
print(count_less_than([], 4)) # Expected Output: 0
print(count_less_than([5, 6, 7, 8], 7)) # Expected Output: 2
print(count_less_than([7, 8, 9], 5)) # Expected Output: 0
Expected outputs:
3
0
2
0
Evaluate the performance of your algorithm and state any strong/weak or future potential work.
- Time Complexity: O(n) where n is the number of elements in the list since we need to iterate through all elements.
- Space Complexity: O(1) as no additional data structures are used beyond the count variable.