fetch projects using graphql

Signed-off-by: Kartikey-star <[email protected]>

Author: Kartikey-star

main.go

@@ -58,22 +58,25 @@ func CallGithubApi() {
 	var listquery struct {
 		Organization struct {
 			Projectv2 struct {
-				Nodes struct {
-					id    string
-					title string
+				Nodes []struct {
+					Id    string
+					Title string
 				}
 			} `graphql:"projectsV2(first: 20)"`
-		} `graphql:"organization(login: \"open-connectors\")"`
+		} `graphql:"organization(login: $orgname)"`
 	}
-	// variables = map[string]interface{}{
-	// 	"orgname": githubv4.String("open-connectors"),
-	// }
-	err = client.Query(context.Background(), &listquery, nil)
+	variables = map[string]interface{}{
+		"orgname": githubv4.String("open-connectors"),
+	}
+	err = client.Query(context.Background(), &listquery, variables)
 	if err != nil {
 		fmt.Println(err)
 	}
-	// fmt.Println(listquery.Organization.Name)
-	fmt.Println(listquery.Organization.Projectv2.Nodes)
+	nodes := listquery.Organization.Projectv2.Nodes
+	for _, node := range nodes {
+		fmt.Println(node.Id)
+		fmt.Println(node.Title)
+	}
 }
 
 // printJSON prints v as JSON encoded with indent to stdout. It panics on any error.