{leetcode}/problems/regular-expression-matching/[LeetCode - Regular Expression Matching^]
Given an input string (s
) and a pattern (p
), implement regular expression matching with support for '.'
and '*'
.
'.' Matches any single character. '*' Matches zero or more of the preceding element.
The matching should cover the entire input string (not partial).
Note:
-
s
could be empty and contains only lowercase lettersa-z
. -
p
could be empty and contains only lowercase lettersa-z
, and characters like.
or*
.
Example 1:
Input: s = "aa" p = "a" Output: false Explanation: "a" does not match the entire string "aa".
Example 2:
Input: s = "aa" p = "a*" Output: true Explanation: '*' means zero or more of the preceding element, 'a'. Therefore, by repeating 'a' once, it becomes "aa".
Example 3:
Input: s = "ab" p = "." *Output: true Explanation: "." means "zero or more () of any character (.)".
Example 4:
Input: s = "aab" p = "c*a*b" Output: true Explanation: c can be repeated 0 times, a can be repeated 1 time. Therefore, it matches "aab".
Example 5:
Input: s = "mississippi" p = "mis*is*p*." Output: false
link:{sourcedir}/_0010_RegularExpressionMatching.java[role=include]