{leetcode}/problems/last-stone-weight-ii/[LeetCode - Last Stone Weight II^]
We have a collection of rocks, each rock has a positive integer weight.
Each turn, we choose any two rocks and smash them together. Suppose the stones have weights x
and y
with x ⇐ y
. The result of this smash is:
-
If
x == y
, both stones are totally destroyed; -
If
x != y
, the stone of weightx
is totally destroyed, and the stone of weighty
has new weighty-x
.
At the end, there is at most 1 stone left. Return the smallest possible weight of this stone (the weight is 0 if there are no stones left.)
Example 1:
Input: [2,7,4,1,8,1] Output: 1 Explanation: We can combine 2 and 4 to get 2 so the array converts to [2,7,1,8,1] then, we can combine 7 and 8 to get 1 so the array converts to [2,1,1,1] then, we can combine 2 and 1 to get 1 so the array converts to [1,1,1] then, we can combine 1 and 1 to get 0 so the array converts to [1] then that's the optimal value.
Note:
-
1 ⇐ stones.length ⇐ 30
-
1 ⇐ stones[i] ⇐ 100
link:{sourcedir}/_1049_LastStoneWeightII.java[role=include]