Skip to content

Latest commit

 

History

History
66 lines (47 loc) · 2.47 KB

1334-find-the-city-with-the-smallest-number-of-neighbors-at-a-threshold-distance.adoc

File metadata and controls

66 lines (47 loc) · 2.47 KB

1334. Find the City With the Smallest Number of Neighbors at a Threshold Distance

{leetcode}/problems/find-the-city-with-the-smallest-number-of-neighbors-at-a-threshold-distance/[LeetCode - Find the City With the Smallest Number of Neighbors at a Threshold Distance^]

There are n cities numbered from 0 to n-1. Given the array edges where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer distanceThreshold.

Return the city with the smallest number* of cities that are reachable through some path and whose distance is *at most distanceThreshold, If there are multiple such cities, return the city with the greatest number.

Notice that the distance of a path connecting cities *i* and *j* is equal to the sum of the edges' weights along that path.

Example 1:

{image_attr}
Input: n = 4, edges = [[0,1,3],[1,2,1],[1,3,4],[2,3,1]], distanceThreshold = 4
Output: 3
Explanation: The figure above describes the graph.
The neighboring cities at a distanceThreshold = 4 for each city are:
City 0 -> [City 1, City 2]
City 1 -> [City 0, City 2, City 3]
City 2 -> [City 0, City 1, City 3]
City 3 -> [City 1, City 2]
Cities 0 and 3 have 2 neighboring cities at a distanceThreshold = 4, but we have to return city 3 since it has the greatest number.

Example 2:

{image_attr}
Input: n = 5, edges = [[0,1,2],[0,4,8],[1,2,3],[1,4,2],[2,3,1],[3,4,1]], distanceThreshold = 2
Output: 0
Explanation: The figure above describes the graph.
The neighboring cities at a distanceThreshold = 2 for each city are:
City 0 -> [City 1]
City 1 -> [City 0, City 4]
City 2 -> [City 3, City 4]
City 3 -> [City 2, City 4]
City 4 -> [City 1, City 2, City 3]
The city 0 has 1 neighboring city at a distanceThreshold = 2.

Constraints:

  • 2 ⇐ n ⇐ 100

  • 1 ⇐ edges.length ⇐ n * (n - 1) / 2

  • edges[i].length == 3

  • 0 ⇐ fromi < toi < n

  • 1 ⇐ weighti, distanceThreshold ⇐ 10^4

  • All pairs (fromi, toi) are distinct.

link:{sourcedir}/_1334_FindTheCityWithTheSmallestNumberOfNeighborsAtAThresholdDistance.java[role=include]