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Solution.js
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/**
* @param {number[]} nums
* @param {number} k
* @return {number}
*/
var minMaxSubarraySum = function (nums, k) {
const computeSum = (nums, k, isMin) => {
const n = nums.length;
const prev = new Array(n).fill(-1);
const next = new Array(n).fill(n);
let stack = [];
if (isMin) {
for (let i = 0; i < n; i++) {
while (stack.length > 0 && nums[stack[stack.length - 1]] >= nums[i]) {
stack.pop();
}
prev[i] = stack.length > 0 ? stack[stack.length - 1] : -1;
stack.push(i);
}
stack = [];
for (let i = n - 1; i >= 0; i--) {
while (stack.length > 0 && nums[stack[stack.length - 1]] > nums[i]) {
stack.pop();
}
next[i] = stack.length > 0 ? stack[stack.length - 1] : n;
stack.push(i);
}
} else {
for (let i = 0; i < n; i++) {
while (stack.length > 0 && nums[stack[stack.length - 1]] <= nums[i]) {
stack.pop();
}
prev[i] = stack.length > 0 ? stack[stack.length - 1] : -1;
stack.push(i);
}
stack = [];
for (let i = n - 1; i >= 0; i--) {
while (stack.length > 0 && nums[stack[stack.length - 1]] < nums[i]) {
stack.pop();
}
next[i] = stack.length > 0 ? stack[stack.length - 1] : n;
stack.push(i);
}
}
let sum = 0;
for (let i = 0; i < n; i++) {
const left = prev[i];
const right = next[i];
const a = left + 1;
const b = i;
const c = i;
const d = right - 1;
let s_start = Math.max(a, i - k + 1);
let s_end_candidate = d - k + 1;
let s_upper = Math.min(b, s_end_candidate);
let sum1 = 0;
if (s_upper >= s_start) {
const num_terms = s_upper - s_start + 1;
const first = s_start;
const last = s_upper;
const sum_s = (last * (last + 1)) / 2 - ((first - 1) * first) / 2;
const sum_k = (k - i) * num_terms;
sum1 = sum_s + sum_k;
}
let s2_start = s_upper + 1;
let s2_end = b;
s2_start = Math.max(s2_start, a);
s2_end = Math.min(s2_end, b);
let sum2 = 0;
if (s2_start <= s2_end) {
const count = s2_end - s2_start + 1;
const term = d - i + 1;
sum2 = term * count;
}
sum += nums[i] * (sum1 + sum2);
}
return sum;
};
const sumMin = computeSum(nums, k, true);
const sumMax = computeSum(nums, k, false);
return sumMin + sumMax;
};