fix: paging address space calculation (#98)

Author: malletgaetan

04_Memory_Management/03_Paging.md

@@ -226,7 +226,7 @@ If we are using 2MB pages this is how the address will be handled by the paging
 * Bits 29 ... 21 are the PD entry.
 * Offset in the page directory.
 
-Every table has 512 elements, so we have an address space of $2^{512}*2^{512}*2^{512}*0x200000$ (that is the page size)
+Every table has 512 elements, so we have an address space of $512*512*512*0x200000$ (that is the page size)
 
 ### Address translation Using 4KB Pages
 
@@ -246,7 +246,7 @@ If we are using 4kB pages this is how the address will be handled by the paging
 * Offset in the page table.
 
 Same as above:
-Every table has 512 elements, so we have an address space of: $2^{512}*2^{512}*2^{512}*2^{512}*0x1000$ (that is the page size)
+Every table has 512 elements, so we have an address space of: $512*512*512*512*0x1000$ (that is the page size)
 
 ## Page Fault
 

99_Appendices/I_Acknowledgments.md

@@ -20,3 +20,4 @@ In no particular order:
 - @AnErrupTion ([https://github.com/AnErrupTion](https://github.com/AnErrupTion))
 - @MRRcode979 ([https://github.com/MRRcode979](https://github.com/MRRcode979))
 - @Hqnnqh ([https://github.com/Hqnnqh](https://github.com/Hqnnqh))
+- @malletgaetan ([https://github.com/malletgaetan](https://github.com/malletgaetan))