-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path227-calculate.go
126 lines (122 loc) · 2.89 KB
/
227-calculate.go
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
// https://leetcode-cn.com/problems/basic-calculator-ii/
package main
import (
"fmt"
"strconv"
)
/**
* 总体思路与官方解答一致, 都是用栈缓存数据
* 但在细节处理上复杂很多
*/
func calculate(s string) int {
var nums []int // 数字栈
var opers []rune // 运算符栈
for i := 0; i < len(s); i++ {
if s[i] >= '0' && s[i] <= '9' {
// 找连续的数字
j := i + 1
for ; j < len(s) && s[j] >= '0' && s[j] <= '9'; j++ {
}
num, err := strconv.Atoi(s[i:j]) // 转换成整型
if err != nil {
break
}
i = j - 1
// 运算符栈为空:直接插入
if len(opers) == 0 {
nums = append(nums, num)
} else {
// 提前处理乘除法
oper := opers[len(opers)-1]
top := nums[len(nums)-1]
if oper == '*' {
nums[len(nums)-1] = num * top
opers = opers[:len(opers)-1]
} else if oper == '/' {
nums[len(nums)-1] = top / num
opers = opers[:len(opers)-1]
} else {
nums = append(nums, num)
}
}
} else if s[i] == '*' || s[i] == '/' { // 乘除法优先级高 直接插入
opers = append(opers, rune(s[i]))
} else if s[i] == '+' || s[i] == '-' { // 加减法优先级低 前面的运算符都需要计算
if len(opers) == 0 {
opers = append(opers, rune(s[i]))
} else {
oper := opers[len(opers)-1]
top := nums[len(nums)-1]
if oper == '*' {
nums[len(nums)-2] *= top
} else if oper == '/' {
nums[len(nums)-2] /= top
} else if oper == '+' {
nums[len(nums)-2] += top
} else {
nums[len(nums)-2] -= top
}
opers[len(opers)-1] = rune(s[i])
nums = nums[:len(nums)-1]
}
} else if s[i] == ' ' {
continue
}
//fmt.Println("nums:", nums, " opers:", opers)
}
for len(opers) > 0 {
oper := opers[len(opers)-1]
top := nums[len(nums)-1]
if oper == '*' {
nums[len(nums)-2] *= top
} else if oper == '/' {
nums[len(nums)-2] /= top
} else if oper == '+' {
nums[len(nums)-2] += top
} else if oper == '-' {
nums[len(nums)-2] -= top
}
opers = opers[:len(opers)-1]
nums = nums[:len(nums)-1]
}
return nums[len(nums)-1]
}
/**
* 官方解答 更简洁
* 把减法变成加法这种处理特别好,极大地简化了代码,省掉了操作符栈
*/
func calculate2(s string) (ans int) {
stack := []int{}
preSign := '+'
num := 0
for i, ch := range s {
isDigit := '0' <= ch && ch <= '9'
if isDigit {
num = num*10 + int(ch-'0')
}
if !isDigit && ch != ' ' || i == len(s)-1 {
switch preSign {
case '+':
stack = append(stack, num)
case '-':
stack = append(stack, -num)
case '*':
stack[len(stack)-1] *= num
default:
stack[len(stack)-1] /= num
}
preSign = ch
num = 0
}
}
for _, v := range stack {
ans += v
}
return
}
func main() {
ss := []string{"3+2*2", " 3/2 ", " 3+5 / 2 ", "42", "33+20*22-5", "1-1+1", "14/3*2"}
for _, s := range ss {
fmt.Println(s, "=", calculate(s), calculate2(s))
}
}