Update Python Program to Sort Words in Alphabetic Order.py

Changes: 
>Removes punctuation
>Sorts all words alphabetically by using consistent case (.lower())
>Ignores duplicate words
>Output is a dictionary which assigns each alphabetized word (value) a respective number (key)

Author: AndrewB50

Python Program to Sort Words in Alphabetic Order.py

@@ -1,18 +1,42 @@
-# Program to sort alphabetically the words form a string provided by the user
+# Program to sort words alphabetically and put them in a dictionary with corresponding numbered keys
+# We are also removing punctuation to ensure the desired output, without importing a library for assistance. 
 
-my_str = "Hello this Is an Example With cased letters"
+# Declare base variables
+word_Dict = {}
+count = 0
+my_str = "Hello this Is an Example With cased letters. Hello, this is a good string"
+#Initialize punctuation
+punctuations = '''!()-[]{};:'",<>./?@#$%^&*_~'''
 
 # To take input from the user
 #my_str = input("Enter a string: ")
 
+# remove punctuation from the string and use an empty variable to put the alphabetic characters into
+no_punct = ""
+for char in my_str:
+   if char not in punctuations:
+       no_punct = no_punct + char
+
+# Make all words in string lowercase. my_str now equals the original string without the punctuation 
+my_str = no_punct.lower()
+
 # breakdown the string into a list of words
 words = my_str.split()
 
-# sort the list
+# sort the list and remove duplicate words
 words.sort()
 
-# display the sorted words
-
-print("The sorted words are:")
+new_Word_List = []
 for word in words:
-   print(word)
+    if word not in new_Word_List:
+        new_Word_List.append(word)
+    else:
+        continue
+
+# insert sorted words into dictionary with key
+
+for word in new_Word_List:
+    count+=1
+    word_Dict[count] = word
+
+print(word_Dict)