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| 1 | +// CPP program to implement Strassen’s Matrix |
| 2 | +// Multiplication Algorithm |
| 3 | +#include <bits/stdc++.h> |
| 4 | +using namespace std; |
| 5 | +typedef long long lld; |
| 6 | + |
| 7 | +/* Strassen's Algorithm for matrix multiplication |
| 8 | +Complexity: O(n^2.808) */ |
| 9 | + |
| 10 | +inline lld** MatrixMultiply(lld** a, lld** b, int n, int l, int m) |
| 11 | +{ |
| 12 | + lld** c = new lld*[n]; |
| 13 | + for (int i = 0; i < n; i++) |
| 14 | + c[i] = new lld[m]; |
| 15 | + |
| 16 | + for (int i = 0; i < n; i++) { |
| 17 | + for (int j = 0; j < m; j++) { |
| 18 | + c[i][j] = 0; |
| 19 | + for (int k = 0; k < l; k++) { |
| 20 | + c[i][j] += a[i][k] * b[k][j]; |
| 21 | + } |
| 22 | + } |
| 23 | + } |
| 24 | + return c; |
| 25 | +} |
| 26 | + |
| 27 | +inline lld** Strassen(lld** a, lld** b, int n, int l, int m) |
| 28 | +{ |
| 29 | + if (n == 1 || l == 1 || m == 1) |
| 30 | + return MatrixMultiply(a, b, n, l, m); |
| 31 | + |
| 32 | + lld** c = new lld*[n]; |
| 33 | + for (int i = 0; i < n; i++) |
| 34 | + c[i] = new lld[m]; |
| 35 | + |
| 36 | + int adjN = (n >> 1) + (n & 1); |
| 37 | + int adjL = (l >> 1) + (l & 1); |
| 38 | + int adjM = (m >> 1) + (m & 1); |
| 39 | + |
| 40 | + lld**** As = new lld***[2]; |
| 41 | + for (int x = 0; x < 2; x++) { |
| 42 | + As[x] = new lld**[2]; |
| 43 | + for (int y = 0; y < 2; y++) { |
| 44 | + As[x][y] = new lld*[adjN]; |
| 45 | + for (int i = 0; i < adjN; i++) { |
| 46 | + As[x][y][i] = new lld[adjL]; |
| 47 | + for (int j = 0; j < adjL; j++) { |
| 48 | + int I = i + (x & 1) * adjN; |
| 49 | + int J = j + (y & 1) * adjL; |
| 50 | + As[x][y][i][j] = (I < n && J < l) ? a[I][J] : 0; |
| 51 | + } |
| 52 | + } |
| 53 | + } |
| 54 | + } |
| 55 | + |
| 56 | + lld**** Bs = new lld***[2]; |
| 57 | + for (int x = 0; x < 2; x++) { |
| 58 | + Bs[x] = new lld**[2]; |
| 59 | + for (int y = 0; y < 2; y++) { |
| 60 | + Bs[x][y] = new lld*[adjN]; |
| 61 | + for (int i = 0; i < adjL; i++) { |
| 62 | + Bs[x][y][i] = new lld[adjM]; |
| 63 | + for (int j = 0; j < adjM; j++) { |
| 64 | + int I = i + (x & 1) * adjL; |
| 65 | + int J = j + (y & 1) * adjM; |
| 66 | + Bs[x][y][i][j] = (I < l && J < m) ? b[I][J] : 0; |
| 67 | + } |
| 68 | + } |
| 69 | + } |
| 70 | + } |
| 71 | + |
| 72 | + lld*** s = new lld**[10]; |
| 73 | + for (int i = 0; i < 10; i++) { |
| 74 | + switch (i) { |
| 75 | + case 0: |
| 76 | + s[i] = new lld*[adjL]; |
| 77 | + for (int j = 0; j < adjL; j++) { |
| 78 | + s[i][j] = new lld[adjM]; |
| 79 | + for (int k = 0; k < adjM; k++) { |
| 80 | + s[i][j][k] = Bs[0][1][j][k] - Bs[1][1][j][k]; |
| 81 | + } |
| 82 | + } |
| 83 | + break; |
| 84 | + case 1: |
| 85 | + s[i] = new lld*[adjN]; |
| 86 | + for (int j = 0; j < adjN; j++) { |
| 87 | + s[i][j] = new lld[adjL]; |
| 88 | + for (int k = 0; k < adjL; k++) { |
| 89 | + s[i][j][k] = As[0][0][j][k] + As[0][1][j][k]; |
| 90 | + } |
| 91 | + } |
| 92 | + break; |
| 93 | + case 2: |
| 94 | + s[i] = new lld*[adjN]; |
| 95 | + for (int j = 0; j < adjN; j++) { |
| 96 | + s[i][j] = new lld[adjL]; |
| 97 | + for (int k = 0; k < adjL; k++) { |
| 98 | + s[i][j][k] = As[1][0][j][k] + As[1][1][j][k]; |
| 99 | + } |
| 100 | + } |
| 101 | + break; |
| 102 | + case 3: |
| 103 | + s[i] = new lld*[adjL]; |
| 104 | + for (int j = 0; j < adjL; j++) { |
| 105 | + s[i][j] = new lld[adjM]; |
| 106 | + for (int k = 0; k < adjM; k++) { |
| 107 | + s[i][j][k] = Bs[1][0][j][k] - Bs[0][0][j][k]; |
| 108 | + } |
| 109 | + } |
| 110 | + break; |
| 111 | + case 4: |
| 112 | + s[i] = new lld*[adjN]; |
| 113 | + for (int j = 0; j < adjN; j++) { |
| 114 | + s[i][j] = new lld[adjL]; |
| 115 | + for (int k = 0; k < adjL; k++) { |
| 116 | + s[i][j][k] = As[0][0][j][k] + As[1][1][j][k]; |
| 117 | + } |
| 118 | + } |
| 119 | + break; |
| 120 | + case 5: |
| 121 | + s[i] = new lld*[adjL]; |
| 122 | + for (int j = 0; j < adjL; j++) { |
| 123 | + s[i][j] = new lld[adjM]; |
| 124 | + for (int k = 0; k < adjM; k++) { |
| 125 | + s[i][j][k] = Bs[0][0][j][k] + Bs[1][1][j][k]; |
| 126 | + } |
| 127 | + } |
| 128 | + break; |
| 129 | + case 6: |
| 130 | + s[i] = new lld*[adjN]; |
| 131 | + for (int j = 0; j < adjN; j++) { |
| 132 | + s[i][j] = new lld[adjL]; |
| 133 | + for (int k = 0; k < adjL; k++) { |
| 134 | + s[i][j][k] = As[0][1][j][k] - As[1][1][j][k]; |
| 135 | + } |
| 136 | + } |
| 137 | + break; |
| 138 | + case 7: |
| 139 | + s[i] = new lld*[adjL]; |
| 140 | + for (int j = 0; j < adjL; j++) { |
| 141 | + s[i][j] = new lld[adjM]; |
| 142 | + for (int k = 0; k < adjM; k++) { |
| 143 | + s[i][j][k] = Bs[1][0][j][k] + Bs[1][1][j][k]; |
| 144 | + } |
| 145 | + } |
| 146 | + break; |
| 147 | + case 8: |
| 148 | + s[i] = new lld*[adjN]; |
| 149 | + for (int j = 0; j < adjN; j++) { |
| 150 | + s[i][j] = new lld[adjL]; |
| 151 | + for (int k = 0; k < adjL; k++) { |
| 152 | + s[i][j][k] = As[0][0][j][k] - As[1][0][j][k]; |
| 153 | + } |
| 154 | + } |
| 155 | + break; |
| 156 | + case 9: |
| 157 | + s[i] = new lld*[adjL]; |
| 158 | + for (int j = 0; j < adjL; j++) { |
| 159 | + s[i][j] = new lld[adjM]; |
| 160 | + for (int k = 0; k < adjM; k++) { |
| 161 | + s[i][j][k] = Bs[0][0][j][k] + Bs[0][1][j][k]; |
| 162 | + } |
| 163 | + } |
| 164 | + break; |
| 165 | + } |
| 166 | + } |
| 167 | + |
| 168 | + lld*** p = new lld**[7]; |
| 169 | + p[0] = Strassen(As[0][0], s[0], adjN, adjL, adjM); |
| 170 | + p[1] = Strassen(s[1], Bs[1][1], adjN, adjL, adjM); |
| 171 | + p[2] = Strassen(s[2], Bs[0][0], adjN, adjL, adjM); |
| 172 | + p[3] = Strassen(As[1][1], s[3], adjN, adjL, adjM); |
| 173 | + p[4] = Strassen(s[4], s[5], adjN, adjL, adjM); |
| 174 | + p[5] = Strassen(s[6], s[7], adjN, adjL, adjM); |
| 175 | + p[6] = Strassen(s[8], s[9], adjN, adjL, adjM); |
| 176 | + |
| 177 | + for (int i = 0; i < adjN; i++) { |
| 178 | + for (int j = 0; j < adjM; j++) { |
| 179 | + c[i][j] = p[4][i][j] + p[3][i][j] - p[1][i][j] + p[5][i][j]; |
| 180 | + if (j + adjM < m) |
| 181 | + c[i][j + adjM] = p[0][i][j] + p[1][i][j]; |
| 182 | + if (i + adjN < n) |
| 183 | + c[i + adjN][j] = p[2][i][j] + p[3][i][j]; |
| 184 | + if (i + adjN < n && j + adjM < m) |
| 185 | + c[i + adjN][j + adjM] = p[4][i][j] + p[0][i][j] - p[2][i][j] - p[6][i][j]; |
| 186 | + } |
| 187 | + } |
| 188 | + |
| 189 | + for (int x = 0; x < 2; x++) { |
| 190 | + for (int y = 0; y < 2; y++) { |
| 191 | + for (int i = 0; i < adjN; i++) { |
| 192 | + delete[] As[x][y][i]; |
| 193 | + } |
| 194 | + delete[] As[x][y]; |
| 195 | + } |
| 196 | + delete[] As[x]; |
| 197 | + } |
| 198 | + delete[] As; |
| 199 | + |
| 200 | + for (int x = 0; x < 2; x++) { |
| 201 | + for (int y = 0; y < 2; y++) { |
| 202 | + for (int i = 0; i < adjL; i++) { |
| 203 | + delete[] Bs[x][y][i]; |
| 204 | + } |
| 205 | + delete[] Bs[x][y]; |
| 206 | + } |
| 207 | + delete[] Bs[x]; |
| 208 | + } |
| 209 | + delete[] Bs; |
| 210 | + |
| 211 | + for (int i = 0; i < 10; i++) { |
| 212 | + switch (i) { |
| 213 | + case 0: |
| 214 | + case 3: |
| 215 | + case 5: |
| 216 | + case 7: |
| 217 | + case 9: |
| 218 | + for (int j = 0; j < adjL; j++) { |
| 219 | + delete[] s[i][j]; |
| 220 | + } |
| 221 | + break; |
| 222 | + case 1: |
| 223 | + case 2: |
| 224 | + case 4: |
| 225 | + case 6: |
| 226 | + case 8: |
| 227 | + for (int j = 0; j < adjN; j++) { |
| 228 | + delete[] s[i][j]; |
| 229 | + } |
| 230 | + break; |
| 231 | + } |
| 232 | + delete[] s[i]; |
| 233 | + } |
| 234 | + delete[] s; |
| 235 | + |
| 236 | + for (int i = 0; i < 7; i++) { |
| 237 | + for (int j = 0; j < (n >> 1); j++) { |
| 238 | + delete[] p[i][j]; |
| 239 | + } |
| 240 | + delete[] p[i]; |
| 241 | + } |
| 242 | + delete[] p; |
| 243 | + |
| 244 | + return c; |
| 245 | +} |
| 246 | + |
| 247 | +int main() |
| 248 | +{ |
| 249 | + lld** matA; |
| 250 | + matA = new lld*[2]; |
| 251 | + for (int i = 0; i < 2; i++) |
| 252 | + matA[i] = new lld[3]; |
| 253 | + matA[0][0] = 1; |
| 254 | + matA[0][1] = 2; |
| 255 | + matA[0][2] = 3; |
| 256 | + matA[1][0] = 4; |
| 257 | + matA[1][1] = 5; |
| 258 | + matA[1][2] = 6; |
| 259 | + |
| 260 | + lld** matB; |
| 261 | + matB = new lld*[3]; |
| 262 | + for (int i = 0; i < 3; i++) |
| 263 | + matB[i] = new lld[2]; |
| 264 | + matB[0][0] = 7; |
| 265 | + matB[0][1] = 8; |
| 266 | + matB[1][0] = 9; |
| 267 | + matB[1][1] = 10; |
| 268 | + matB[2][0] = 11; |
| 269 | + matB[2][1] = 12; |
| 270 | + |
| 271 | + lld** matC = Strassen(matA, matB, 2, 3, 2); |
| 272 | + for (int i = 0; i < 2; i++) { |
| 273 | + for (int j = 0; j < 2; j++) { |
| 274 | + printf("%lld ", matC[i][j]); |
| 275 | + } |
| 276 | + printf("\n"); |
| 277 | + } |
| 278 | + |
| 279 | + return 0; |
| 280 | +} |
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