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[#3209] Further review comments
modified: encode/encode.cc
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src/lib/util/encode/encode.cc

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@@ -106,7 +106,7 @@ BaseNEncoder::encode(const std::vector<uint8_t>& input) {
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} else {
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// No, the index is complete, lookup its digit and add it to the
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// output. Start over for the next index.
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encoded_output.push_back(digit_set_[digit_idx]);
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encoded_output.push_back(bitsToDigit(digit_idx));
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digit_idx = 0;
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cnt = 0;
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}
@@ -149,7 +149,7 @@ BaseNEncoder::encode(const std::vector<uint8_t>& input) {
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void
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BaseNEncoder::decode(const std::string& encoded_str, std::vector<uint8_t>& output) {
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// Mechanics are the essentially the same as encode(). We iterate over the encoded
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// Mechanics are essentially the same as encode(). We iterate over the encoded
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// string's digits, discarding whitespaces. We lookup the digit's binary value
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// in the lookup table, keeping only binary value's right-most, bits_per_digit bits.
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// The remaining bits are then shifted out from the left of binary value into the
@@ -250,10 +250,10 @@ BaseNEncoder::decode(const std::string& encoded_str, std::vector<uint8_t>& outpu
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// The number of bits for the '==...' part is padchars * BitsPerChunk.
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// So the total number of pad bits is the smallest multiple of 8
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// that is >= padchars * BitsPerChunk.
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// (Below, note the common idiom of the bitwise AND with ~7. It clears the
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// (Below, note the common idiom of the bitwise AND with ~0x7. It clears the
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// lowest three bits, so has the effect of rounding the result down to the
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// nearest multiple of 8)
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const size_t padbits = ((pad_cnt * bits_per_digit_) + 0x07) & ~0x07;
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const size_t padbits = ((pad_cnt * bits_per_digit_) + 7) & ~0x7;
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if (padbits > bits_per_digit_ * (pad_cnt + 1)) {
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isc_throw(isc::BadValue, "Invalid padding for "
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<< algorithm_ << ": " << encoded_str);

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