Birthday Paradox

Author: ivorynoise

birthdayParadox-h.cpp

@@ -0,0 +1,20 @@
+#include<iostream>
+#include<stdio.h>
+using namespace std;
+
+
+int main(){
+    int cur_day=365;
+    double ans=1.0,a1=1.00;
+    for(int i=0;i<80;i++){
+        if(i!=0 && i%5==0){
+             cout<<i<<" ";
+             printf("%.13lf\n",1.00-ans);
+            
+        }
+        //cout<<cur_day<<" ";
+        ans*=(double)(cur_day/365.00);
+        cur_day--;
+    }
+    return 0;
+}

birthdayParadox-r.cpp

@@ -0,0 +1,49 @@
+// a room conatains n no of people and 
+
+
+// 1 what is no of peaople required at least to make sure that 100% two people have bday on same date
+
+//366
+
+// the probability of  two people among group has same probbaility
+
+
+
+
+// 1- (365/364);
+
+
+/* Unsorted Array 
+					Unlike other Coders No logic at all !
+															Find and run 
+
+*/
+#include<bits/stdc++.h>
+using namespace std;
+void calculateProb(int i)
+{
+	double val=1;
+	for(int j=0;j<i;j++)
+	{
+		val = val*(365-j)/365;
+	}
+	printf("%0.12f",1-val);
+}
+int main()
+{
+
+		for(int i=5;i<=75;i+=5)
+		{
+			printf("%d ",i );
+			calculateProb(i);
+			cout<<endl;
+
+		}
+
+
+}
+
+/*Unsorted Array 
+			signing out  all hail !
+									may the judge have mercy on your code 
+																p.s @unsorted array no rights 		reserved */