minor

Author: iliakan

1-js/08-prototypes/02-function-prototype/4-new-object-same-constructor/solution.md

@@ -15,7 +15,7 @@ alert( user2.name ); // Pete (worked!)
 
 It worked, because `User.prototype.constructor == User`.
 
-..But if someone, so to speak, overwrites `User.prototype` and forgets to recreate `"constructor"`, then it would fail.
+..But if someone, so to speak, overwrites `User.prototype` and forgets to recreate `constructor` to reference `User`, then it would fail.
 
 For instance:
 
@@ -41,4 +41,4 @@ Here's how `new user.constructor('Pete')` works:
 2. Then it follows the prototype chain. The prototype of `user` is `User.prototype`, and it also has nothing.
 3. The value of `User.prototype` is a plain object `{}`, its prototype is `Object.prototype`. And there is `Object.prototype.constructor == Object`. So it is used.
 
-At the end, we have `let user2 = new Object('Pete')`. The built-in `Object` constructor ignores arguments, it always creates an empty object -- that's what we have in `user2` after all.
+At the end, we have `let user2 = new Object('Pete')`. The built-in `Object` constructor ignores arguments, it always creates an empty object, similar to `let user2 = {}`, that's what we have in `user2` after all.