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4_Sum.cpp
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/*
Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target.
Note
Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie, a ≤ b ≤ c ≤ d)
The solution set must not contain duplicate quadruplets.
Example
For example, given array S = {1 0 -1 0 -2 2}, and target = 0. A solution set is:
(-1, 0, 0, 1)
(-2, -1, 1, 2)
(-2, 0, 0, 2)
*/
#include <vector>
#include <algorithm>
using namespace std;
class Solution {
public:
/**
* @param numbers: Give an array numbersbers of n integer
* @param target: you need to find four elements that's sum of target
* @return: Find all unique quadruplets in the array which gives the sum of zero.
*/
vector<vector<int> > fourSum(vector<int> nums, int target) {
// write your code here
vector<vector<int> > result;
if (nums.size() < 4) {
return result;
}
sort(nums.begin(), nums.end());
for (int i = 0; i <= nums.size() - 3; i++) {
if (i > 0 && nums[i] == nums[i - 1]) {
continue;
}
int a = nums[i];
for (int j = i + 1; j <= nums.size() - 2; j++) {
if (j > i + 1 && nums[j] == nums[j - 1]) {
continue;
}
int b = nums[j];
int c_index = j + 1;
int d_index = nums.size() - 1;
while (c_index < d_index) {
if (a + b + nums[c_index] + nums[d_index] == target) {
vector<int> newSolution = {a, b, nums[c_index], nums[d_index]};
if (find(result.begin(), result.end(), newSolution) == result.end()) {
result.push_back(newSolution);
}
c_index++;
d_index--;
} else if (a + b + nums[c_index] + nums[d_index] > target) {
d_index--;
} else {
c_index++;
}
}
}
}
return result;
}
};