10808_알파벳 개수.ipynb

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     "text": [
      "baekjoon\n",
      "1 1 0 0 1 0 0 0 0 1 1 0 0 1 2 0 0 0 0 0 0 0 0 0 0 0\n"
     ]
    }
   ],
   "source": [
    "li = [0]*26\n",
    "for c in input():\n",
    "      li[ord(c)-ord('a')] += 1\n",
    "print(*li)"
   ]
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