10809_알파벳 찾기.ipynb

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      "baekjoon\n",
      "1 0 -1 -1 2 -1 -1 -1 -1 4 3 -1 -1 7 5 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 "
     ]
    }
   ],
   "source": [
    "a = ord('a')\n",
    "li = [-1]*26\n",
    "word = input()\n",
    "for l in word:\n",
    "    li[ord(l)-a] = word.find(l)\n",
    "for n in li:\n",
    "    print(n, end = ' ')"
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