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| 1 | +package code; |
| 2 | +/* |
| 3 | + * 912. Sort an Array |
| 4 | + * 题意:数组排序 |
| 5 | + * 难度:Medium |
| 6 | + * 分类: |
| 7 | + * 思路: |
| 8 | + * Tips:注意和lc215区别 |
| 9 | + * lc215 |
| 10 | + */ |
| 11 | +public class lc912 { |
| 12 | + public static void main(String[] args) { |
| 13 | + int[] arr = sortArray2(new int[]{5,2,3,1}); |
| 14 | + for(int i: arr){ |
| 15 | + System.out.println(i); |
| 16 | + } |
| 17 | + } |
| 18 | + |
| 19 | + // 快排 |
| 20 | + public int[] sortArray(int[] nums) { |
| 21 | + quickSort(nums, 0, nums.length-1); |
| 22 | + return nums; |
| 23 | + } |
| 24 | + public void quickSort(int[] nums, int left, int right){ |
| 25 | + if(left>=right) return; //注意返回 |
| 26 | + int l = left; |
| 27 | + int r = right; |
| 28 | + int pivot = nums[left]; |
| 29 | + while(left<right){ |
| 30 | + while(left<right && nums[right]>=pivot) right--; |
| 31 | + int temp = nums[right]; nums[right] = nums[left]; nums[left]=temp; //交换 |
| 32 | + while(left<right && nums[left]<pivot ) left++; |
| 33 | + temp = nums[right]; nums[right] = nums[left]; nums[left]=temp; |
| 34 | + } |
| 35 | + nums[left] = pivot; |
| 36 | + quickSort(nums, left+1, r); |
| 37 | + quickSort(nums, l, right-1); |
| 38 | + } |
| 39 | + |
| 40 | + // 归并 |
| 41 | + public static int[] sortArray2(int[] nums) { |
| 42 | + mergeSort(nums, 0, nums.length-1); |
| 43 | + return nums; |
| 44 | + } |
| 45 | + public static void mergeSort(int[] nums, int left, int right){ |
| 46 | + if(left<right) { |
| 47 | + int mid = (left+right)/2; |
| 48 | + mergeSort(nums, left, mid); |
| 49 | + mergeSort(nums, mid+1, right); |
| 50 | + merge(nums, left, mid, right); |
| 51 | + } |
| 52 | + } |
| 53 | + public static void merge(int[] nums, int left, int mid, int right){ |
| 54 | + int[] temp = nums.clone(); //记住这个方法 |
| 55 | + int cur = left; |
| 56 | + int pos1 = left; |
| 57 | + int pos2 = mid+1; |
| 58 | + while(pos1<=mid && pos2<=right){ |
| 59 | + if(temp[pos1]<temp[pos2]) { //注意是temp 复制后的 |
| 60 | + nums[cur] = temp[pos1]; |
| 61 | + pos1++; |
| 62 | + cur++; |
| 63 | + } |
| 64 | + else { |
| 65 | + nums[cur] = temp[pos2]; |
| 66 | + pos2++; |
| 67 | + cur++; |
| 68 | + } |
| 69 | + } |
| 70 | + while(pos1<=mid){ |
| 71 | + nums[cur] = temp[pos1]; |
| 72 | + pos1++; |
| 73 | + cur++; |
| 74 | + } |
| 75 | + while(pos2<=right){ |
| 76 | + nums[cur] = temp[pos2]; |
| 77 | + pos2++; |
| 78 | + cur++; |
| 79 | + } |
| 80 | + } |
| 81 | +} |
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