Create distance_phrases.py

Author: masterpol

Diff for: distance_phrases.py

@@ -0,0 +1,31 @@
+from typing import List
+
+'''
+    take a function that recieve and input a list with strings and a distance and return if the input contains
+    the list of of strings with less or equal between other phrases. 
+'''
+
+def check_distance(input: str, items: List[str], distance: int) -> bool:
+    entries = input.split(' ');
+    current_item = 0
+    positions = []
+    for i, entry in enumerate(entries):
+        if (entry == items[current_item]):
+            positions.append(i)
+            if (len(positions) > 1 and positions[-1] - (positions[-2] + 1) > distance):
+                break;
+            current_item += 1
+
+    if (len(items) > len(positions)):
+        return False
+
+    return True
+
+
+print(check_distance('should i I take one two aspirine second i or i', ['i', 'take', 'aspirine', 'i', 'i'], 0)) # False
+
+print(check_distance('should i I take one two aspirine second i or i', ['i', 'take', 'aspirine', 'i', 'i'], 2)) # True
+
+print(check_distance('should i I take one two aspirine second second second i or i', ['i', 'take', 'aspirine', 'i', 'i'], 2)) # False
+
+print(check_distance('should i I take one two aspirine second second second i or i', ['i', 'take', 'aspirine', 'i', 'i'], 5)) # True