Create: 1930-unique-length-3-palindromic

Author: Mohammed785

javascript/1930-unique-length-3-palindromic-subsequences.js

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+/**
+ * @param {string} s
+ * @return {number}
+ */
+var countPalindromicSubsequence = function (s) {
+    let count = 0;
+    let chars = new Set(s);
+    for(const char of chars){
+        let first = s.indexOf(char),last = s.lastIndexOf(char);
+        count += new Set(s.slice(first + 1, last)).size;
+    }
+    return count;
+};

python/1930-unique-length-3-palindromic-subsequences.py

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+class Solution:
+    def countPalindromicSubsequence(self, s: str) -> int:
+        count = 0
+        chars = set(s)
+        for char in chars:
+            first,last = s.find(char),s.rfind(char)
+            count += len(set(s[first+1:last]))
+        return count

rust/1930-unique-length-3-palindromic-subsequences.rs

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+use std::iter::FromIterator;
+
+impl Solution {
+    pub fn count_palindromic_subsequence(s: String) -> i32 {
+        let mut result = 0;
+        let mut ranges: [(i32, i32); 26] = [(-1, -1); 26];
+
+        for (i, c) in s.chars().enumerate() {
+            let ix = Solution::char_to_index(c) as usize;
+            if ranges[ix].0 == -1 {
+                ranges[ix].0 = i as i32;
+            }
+            if i as i32 > ranges[ix].1 {
+                ranges[ix].1 = i as i32;
+            }
+        }
+
+        for range in ranges {
+            if range.1 > range.0 {
+                let mut set: u32 = 0;
+                for c in s[range.0 as usize + 1..range.1 as usize].chars() {
+                    set |= 1 << Solution::char_to_index(c);
+                }
+                result += set.count_ones() as i32;
+            }
+        }
+
+        result
+    }
+
+    pub fn char_to_index(c: char) -> u32 {
+        c as u32 - 'a' as u32
+    }
+}

typescript/1930-unique-length-3-palindromic-subsequences.ts

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+function countPalindromicSubsequence(s: string): number {
+    const alphabets = 'abcdefghijklmnopqrstuvwxyz';
+
+    const N = alphabets.length;
+    let count = 0;
+
+    for (let i = 0; i < N; i += 1) {
+        const ch = alphabets[i];
+        const left = s.indexOf(ch);
+        const right = s.lastIndexOf(ch);
+        if (left < right) {
+            for (const alpha of alphabets) {
+                const mid = s.indexOf(alpha, left + 1);
+                if (mid !== -1 && mid < right) count += 1;
+            }
+        }
+    }
+
+    return count;
+}