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1 | 1 | class Solution {
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2 | 2 | public:
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3 |
| - vector<vector<int>> res; |
4 |
| - |
5 |
| - vector<vector<int>> fourSum(vector<int>& nums, int target) { |
6 |
| - |
7 |
| - if(nums.size() < 4) return res; |
8 |
| - |
9 |
| - vector<int>quad; |
10 |
| - sort(nums.begin() , nums.end()); |
11 |
| - kSum(0,4,target,nums,quad); |
12 |
| - return res; |
13 |
| - } |
14 |
| - |
15 |
| - |
16 |
| - void kSum (int index , int k , long long target, vector<int> nums , vector<int>&q) |
17 |
| - { |
18 |
| - |
19 |
| - if(k == 2) |
20 |
| - { |
21 |
| - twoSum(index , target, q , nums); |
22 |
| - return; |
23 |
| - } |
24 |
| - |
25 |
| - for(int i = index ; i < nums.size() - k + 1; i++) |
26 |
| - { |
27 |
| - if(i > index && nums[i] == nums[i-1]) continue; |
28 |
| - q.push_back(nums[i]); |
29 |
| - kSum(i+1 , k-1 , target-nums[i] , nums , q); |
30 |
| - q.pop_back(); |
31 |
| - } |
32 |
| - |
33 |
| - } |
34 |
| - |
35 |
| - void twoSum (int start,long long target,vector<int>&ans,vector<int>& nums) |
36 |
| - { |
37 |
| - int lo = start; |
38 |
| - int hi = nums.size()-1; |
39 |
| - |
40 |
| - while(lo < hi) |
41 |
| - { |
42 |
| - int sum = nums[lo]+nums[hi]; |
43 |
| - if(sum > target) hi--; |
44 |
| - else if (sum < target) lo++; |
45 |
| - |
46 |
| - else |
47 |
| - { |
48 |
| - ans.insert(ans.end() , {nums[lo] , nums[hi]}); |
49 |
| - res.push_back(ans); |
| 3 | + string longestCommonPrefix(vector<string>& strs) { |
| 4 | + string result = strs[0]; |
| 5 | + int charIndex = 0; |
50 | 6 |
|
51 |
| - ans.pop_back(); |
52 |
| - ans.pop_back(); |
53 |
| - |
54 |
| - lo++; |
55 |
| - while (lo < hi && nums[lo] == nums[lo - 1]) lo++; |
56 |
| - } |
57 |
| - } |
58 |
| - } |
| 7 | + //finding minimum string length - that could be max common prefix |
| 8 | + long maxCharIndex = strs[0].length(); |
| 9 | + for (int i = 1; i < strs.size(); ++i) { |
| 10 | + if (strs[i].length() < maxCharIndex) { |
| 11 | + maxCharIndex = strs[i].length(); |
| 12 | + } |
| 13 | + } |
| 14 | + |
| 15 | + while (charIndex < maxCharIndex) { |
| 16 | + char prevChar = strs[0][charIndex]; |
| 17 | + for (int i = 1; i < strs.size(); ++i) { |
| 18 | + if (prevChar == strs[i][charIndex]) { |
| 19 | + continue; |
| 20 | + } |
| 21 | + return result.substr(0, charIndex); |
| 22 | + } |
| 23 | + ++charIndex; |
| 24 | + result += prevChar; |
| 25 | + } |
| 26 | + return result.substr(0, charIndex); |
| 27 | + } |
59 | 28 | };
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