Missing CLDR "other" plural in Russian

[jlowcs]

Describe the issue

Our Weblate instance does not seem to include the CLDR version of Russian (which includes the other plural).

Interestingly, it is present in the demo: https://hosted.weblate.org/languages/ru/#information

Not sure why it's missing on our instance?

I already tried

• I've read and searched the documentation.
• I've searched for similar filed issues in this repository.

Steps to reproduce the behavior

Go to /languages/ru/#information => no CLDR plurals with other

Expected behavior

the CLDR plurals with other should be present

Screenshots

Exception traceback

How do you run Weblate?

Docker container

Weblate versions

5.13.1

Weblate deploy checks

Additional context

No response

[jlowcs]

Actually, it seems like the CLDR version in https://hosted.weblate.org/languages/ru/#information is wrong as it does not match the rules from https://www.unicode.org/cldr/charts/47/supplemental/language_plural_rules.html#ru (which also matches what Intl does). The gettext plural formula rule is a better match.

[nijel]

The default plural on https://hosted.weblate.org/languages/ru/#information has one/few/many what matches CLDR. There is CLDR plural with zero which has zero/one/few/other what likely is a bug in naming the last plural in the UI.

[jlowcs]

@nijel it actually does not match CLDR (see https://www.unicode.org/cldr/charts/47/supplemental/language_plural_rules.html#ru).

CLDR says it should be one/few/many/other.

"other" is apparently used for floats (e.g. 1.5).

[nijel]

It is expected, decimal plurals are currently not supported by Weblate, see #7520.

[jlowcs]

I'm not sure I understand the "lack of support". In theory you could still support the import/export of the other plural key, even though the formula doesn't support it, couldn't you?

Wouldn't this kind of formula work? (from the "gettext plural formula" plural rule in https://hosted.weblate.org/languages/ru/#information)

(n%10==1 && n%100!=11 ? 0 : n%10>=2 && n%10<=4 && (n%100<12 || n%100>14) ? 1 : n%10==0 || (n%10>=5 && n%10<=9) || (n%100>=11 && n%100<=14)? 2 : 3)

[jlowcs]

Can I manually update the plural rule in our Weblate instance?

It looks like it should be doable through the API but I haven't tried it yet.

[nijel]

See https://docs.weblate.org/en/latest/admin/languages.html#built-in-language-definitions