难度:中等
https://leetcode-cn.com/problems/binary-tree-zigzag-level-order-traversal/
给你二叉树的根节点 root
,返回其节点值的 锯齿形层序遍历 。(即先从左往右,
再从右往左进行下一层遍历,以此类推,层与层之间交替进行)。
输入:root = [3,9,20,null,null,15,7]
输出:[[3],[20,9],[15,7]]
输入:root = [1]
输出:[[1]]
输入:root = []
输出:[]
/**
* 广度优先遍历
* @desc 时间复杂度 O(N) 空间复杂度 O(N)
* @param root {TreeNode | null}
* @return {number[][]}
*/
export function zigzagLevelOrder(root: TreeNode | null): number[][] {
if (root === null) return [];
const ans: number[][] = [];
const queue: TreeNode[] = [root];
let isOrderLeft = true; // 判断方向
while (queue.length) {
const len = queue.length;
const values: number[] = [];
for (let i = 0; i < len; i++) {
const tree = queue.shift()!;
// 控制插入顺序
isOrderLeft ? values.push(tree.val) : values.unshift(tree.val);
if (tree.left) queue.push(tree.left);
if (tree.right) queue.push(tree.right);
}
isOrderLeft = !isOrderLeft;
ans.push(values);
}
return ans;
}