难度:中等
给你一棵二叉树的根节点 root
,请你返回 层数最深的叶子节点的和 。
输入:root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
输出:15
输入:root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
输出:19
/**
* 深度优先搜索
* @desc 时间复杂度 O(N) 空间复杂度 O(N)
* @param root
* @returns
*/
export function deepestLeavesSum(root: TreeNode | null): number {
let maxLevel = -1
let sum = 0
dfs(root, 0)
return sum
function dfs(node: TreeNode | null, level: number) {
if (!node) return
if (level > maxLevel) {
maxLevel = level
sum = node.val
}
else if (level === maxLevel) {
sum += node.val
}
dfs(node.left, level + 1)
dfs(node.right, level + 1)
}
}
/**
* 广度优先搜索
* @desc 时间复杂度 O(N) 空间复杂度 O(N)
* @param root
* @returns
*/
export function deepestLeavesSum2(root: TreeNode | null): number {
let sum = 0
if (!root) return sum
const queue: TreeNode[] = []
queue.push(root)
while (queue.length) {
sum = 0
const size = queue.length
for (let i = 0; i < size; i++) {
const node = queue.shift()!
sum += node.val
if (node.left)
queue.push(node.left)
if (node.right)
queue.push(node.right)
}
}
return sum
}